<p>hey everybody..
came across 2 of these questions on a SAT practice test n somehow dont know how to begin with.. any help will really b appreciated..
thanks...</p>
<p>1) A sphere with a radius of 4 is inscribed in a cube whose edge length is 8. What is distance from the centre of the sphere to a corner of the cube?</p>
<p>For question 1, you realize that it's like finding the diagonal of a box whose sides are 4. root(16+16+16) = root(16*3) = 4 root 3</p>
<p>For question 2, this graph has the most turns when it crosses the x axis.
\ /
\ /
\ ^ /
\/ \/
Sry, this is my best depiction of a parabola with the portion under the x axis reflected upwards. As you can see, the most points of intersection occurs when the circle is sitting snug in the parabola and the lil' hill, so 3 points of intersection</p>
<p>I think the answer for the second question should be 4. I understand how you can get 3 intersections, but if you just shift the imaginary circle down a little, there will be 4 intersections.</p>
<p>Oh shoot, I'm crazy! Sorry, didn't read the quesion properly, it's intersections not tangents... Ok well if you have a really slim parabola. (sufficiently slim and long that say, the vertex is say at y = -5000, and at y = 5000, x = +- 2, a pretty slim parabola). Now if you put it into the absolute value function, you'll get kinda a thin "W" shape. Then you'll be able to put a circle on it to have 8 intersection points.</p>
<p>ok people i understood ur explanations... thanks a load.. but what i dont get is how u got the graph of =-|ax^2+bx+c|. wud really appreciate help on dat... </p>