SAT May 2009 Math

<p>Ari: I put 1<x<2; since 1.5 + 3 = 1.5 x 3</p>

<p>^ i put that too, but it confused me because it doesnt work for all numbers?</p>

<p>Ohh man, I took a complete guess for that quadratic one and got it right? It’s 12 for sure? haha</p>

<p>it was 1<x<2. hm u seem right for 12, but i mean i graphed 32-x^2 and x^2 and they didnt interesect</p>

<p>well you know it had to be an integer right…
root 6 is irrational</p>

<p>they intersect at 4 and -4</p>

<p>if you graphed it on a calculator your window was probably wrong</p>

<p>Gandhiizrippin, you have to zoom out on the graph, they do intersect</p>

<p>^damn ti-83 official school calculator. why did u guys divide by 2 though?</p>

<p>when you solve for k it was (k/2)^.5</p>

<p>why is it not english</p>

<p>Ghandi- I just plugged in numbers until it didn’t work. It only took like 20 seconds…</p>

<p>what about the one with the rectangle with the triangles in it and you had to find the area? I got 250 I think…each leg of the triangles was 5 radical 2 and if you square that and multiply by .5 then each had an area of 25…so 300-50=250</p>

<p>the two equations were X^2 and a-X^2
you find where they equal and solve and get 2X^2=a so you divide all the choices they give you by 2</p>

<p>understood. thanks a lot. </p>

<p>yes i got 250.</p>

<p>What about the PQ>RS thing or whatever. I skipped that. >_></p>

<p>i got 18 for the quadratic one</p>

<p>^wholegrain. jugding by what peopel just told me 12 is 100% correct.</p>

<p>i had a and b as answer choices for the pq so i assumed a.</p>

<p>i did it and got an isosceles triangle.</p>

<p>so PQ> PR</p>

<p>also, slope=0. i lol’d at that one.</p>

<p>Quadratic one was 12. I’m positive.</p>

<p>@Gandhi</p>

<p>A was definitely the answer- if you make p really close to the line and r skewed to the right, you can see b is not always true. </p>

<p>I loled at slope=0 too :P</p>

<p>The PQ and RS was whatever answer A was I think…the gist of it was that the leg would be greater than the height, though not necessarily greater than any segment on the line that P, Q, or R was on if that makes any sense…it didn’t say that that line had a midpoint…</p>

<p>was PQ>PR choice a? where PQ was like the hypotenuse and PR was the height?</p>