<p>Two dice are tossed. What is the probability that the sum of the two dice is greater than 3?</p>
<p>A) 1/4
B) 3/4
C) 5/6
D) 11/12
E) 1 </p>
<p>Explain please!</p>
<p>The total number of events in the sample space is 36, due to the fundamental counting principle. There are six possible numbers when a die is rolled. When another die is considered, this is 6*6 outcomes so 36. Think of how many ways the sum of the two dice can be 3, then subtract that from the sample space. This is the probability that the sum of two rolled dice will NOT be 3, same thing the question is asking.</p>
<p>That is, the outcomes in which the sums can be less than 3 is 1,1 2,1 and 1,2</p>
<p>So P = 1 - 3/36 = 33/36 = 11/12</p>