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<p>Hey, thanks for clicking, i figured you guys were all pretty smart, please help me with this math problem I'M FREAKING OUT...and I promise to comment on all your posts as long as you tell me when your posting! </p>

<p>Problem: I will describe the picture: A unit circle with three similar right triangles, triangle OCA is a right triangle with vertice C touching the unit circle. Right triangle ODB is a bit large with vertice B lying on the X-axis and touching the unit circle. Triangle OFE is a bit larger still with no vertice touching the unit circle. There is an arbitrary angle and the question asks me to find six line segments whose respective lenghts are sin t, cos t, tan t, cot t, sec t, csc t</p>

<p>PLEASE HELP ME, AT LEAST give me a tip or hint!!
thanks</p>

<p>hahaha, triangle ODB...</p>

<p>I'm not exactly sure what the picture looks like, but keep this in mind...on the unit circle, all radii are equal to 1. Watch for the parts of triangles that will create the ratios you are looking for; focus on sine, cosine, and tangent because the remaining three are just their reciprocals. Let's take sine as an example. If angle "t" is in the center of the circle, and is the base angle of a right triangle, the side opposite t is equivalent to the sine ratio, since sine equals opposite over hypoteneuse and the hypoteneuse is one!</p>

<p>I have no idea if that's jibberish or not, and I'm so sorry I can't get any more specific!!! Good luck!</p>