<p>How do you solve this on the ti-89?</p>
<p>The Acne plumbing Company wills end a team of 3 plumbers to work on a certain job. The company has 4 expereinced plubmers and 4 trainees. If a team consists of 1 expereinced plumber and 2 trainees, how many different such teams are possible?</p>
<p>thanks</p>
<p>4C1*4C2=24</p>
<p>Right?</p>
<p>yeah... this is how it works i think... u make the 4 exp plumbers letters: a, b, c, d. The trainees can be 1, 2, 3, 4. So a team consists of 1 exp/2 trainees. So try out the possibilities for a: a12, a13, a14, a23, a24, a34. 6 possibilities for exp plumber a. It would be same if you did it with any other exp plumber so its just 6 x 4 = 24. I think this is how it works.</p>
<p>of course that doesn't answer your question of how to do it on the ti89 and i have just wasted my time typing out completely irrelevant information. Go me for reading what you wanted after I posted!!!</p>
<p>lol thanks for trying liberty...i know how to do it on the ti83 but on the ti89 for some reason it says 'too few arguments' i dont get what im doing wrong</p>
<p>The functions on 89 are different.</p>
<p>The 83 nCr which operates as x nCr y</p>
<p>The 89 nCr(x,y)</p>
<p>So for solving this on an 89, type:</p>
<p>nCr(4,1)*nCr(4,2)</p>
<p>Then again... it would be far faster to do this by hand. These choose computations are not large.</p>