<p>You can get the answer quickly simply by plugging in, but i would like to see how this would be solved algebraically. </p>
<p>a=b^2c , where a doesnt equal 0 and b doesnt equal 0. , then b/c = ??</p>
<p>A. a/c
b. a/b
c. a/bc
d. a/b^2c
e. a/bc^2</p>
<p>You know the answer is a divided by something, so:</p>
<p>a=b^2c</p>
<p>a/c = b^2</p>
<p>a/(bc) = b</p>
<p>a/(bc^2) = b/c</p>
<p>You're right, not a well-designed question.</p>
<p>Oh. Well, i didn't see it that way. Thanks for the clear explanation.</p>