Accepted! And @ghazistic we should start one
Nervous and excited!
1… more… DAY…
1… more… DAY…
Deferred
deferred
Deferred
deferred
Accepted!!
Accepted! Looking forward to meeting all of you!
Rejected : ( Congrats to all who made it in!
For admitted students, make sure to request to join the official facebook group for Swat 2022! The name is “Swarthmore College Class of 2022”.
@Slopezvald Thanks!
For the people that asked earlier on:
Ok, so I did the math just for fun…y’all can check my work if I’m wrong. This is an approximation based on the data relased last year that 960 students were offered letters of admission, as well as statistics I found on the internet suggesting a 35% acceptance rate for ED, a 10.7% acceptance rate for RD, and a 14% acceptance rate overall. This, by the way, ignores the distinction between ED I and ED II. But still (assuming rate for ED I = rate for ED II – just to get a rough estimate), setting up a system of equations:
.35 X + .107Y = 960 (X being the ED pool, Y being the RD pool)
.14 (X + Y) = 960
960 = .14X + .14Y
(960 - .14X)/.14 = Y
Substituting our value of Y in:
.35X + ((960-.14X)(.107))/.14 = 960
(.14)(960-.35X) = (.107)(960-.14X)
134.4-.049X = 102.72 - .10498X
31.68 - .049X = -.01498X
31.68 = .03402X
X = approximately 931 ED applicants over ED I and ED II
Factoring in a 35% acceptance rate, that would yield 326 accepted students from ED I and ED II
960 = .14 (931 + Y)
829.66 = .14Y
Y = approximately 5926 regular decision applicants
Factoring in a 10.7% acceptance rate, that would give 634 accepted regular decision applicants
And then 634 + 326 gives 960, so I think that’s right but its kinda late and I’m kinda tired. I just wanted to give the math a shot lol
But that doesn’t take deferred into account, whose extra bites of the apple (probably) factor in ED, ED2 and RD
Guys, click below for the official thread for EDII
http://talk.qa.collegeconfidential.com/swarthmore-college/2054295-swarthmore-edii-class-of-2022-official-thread-p1.html?new=1