The oddball questions

<p>So I am starting to go through my final prepping for tomorrow's SAT and that includes going over the more obscure math topics that show up on the SAT. The last time I took the test I was surprised to see a question testing if you could find the contrapositive of a if p then q statement.</p>

<p>I am also wondering if a permutations/combinatorics question will show up. I was going through some questions in the blue book today when I ran into one.</p>

<p>What are some of the questions/subjects that you have seen not included in the college board's overview of the test?</p>

<p>What page was the permutations/combinatorix one that you found on? And I'd say just know distance/work problems. The occasional logic problem will be on there but it won't be a difficult one. And make sure your reasoning skills are up to par ^.^ Most "difficult" questions are all reasoning, and the occasional use of some 7th grade algebra! Oh....and read the question.</p>

<p>pg. 476 - this problem is one of the few that I could get wrong for actually not knowing how to do it (most of my mistakes are mental math errors).</p>

<p>I sat trying to figure out how to do the problem after getting the permutations out to 4<em>4</em>3 (at this point you cannot solve with permutations) before I tried solving with permutations out of order (going from one far side to the other 4<em>3</em>3*2). So you really come to the solution by luck...unless your familiar with permutations/combinatorics problems. Then you could have taken the total permutations (120) and subtracted the total combinations with the solid block on the outside (48)...etc</p>

<p>edit: that's actually the only perms problem I've seen on the test before, but it still makes me nervous that it took me quite a bit of time to solve... :(</p>

<p>just think of how many tiles can be in each position....on one end u have 4 to chose from so therefore you only have 3 to chose for the other end (4<em>3)
then for the middle ones you have 3 for one 2 for the other and then 1 for the last space. SO.....(4</em>3<em>3</em>2*1)
Thats how you do that....i was kinda shocked to see that when i came across it.</p>

<p>My biggest mistake is not reading the question right.....I seriously want to kick myself in the crotch every time it happens. Because the questions are really not that hard at all!!</p>

<p>I know exactly what you mean zfox! I hate it when I see that I get 2 'easy' problems wrong but all the 'hard' problems right.</p>