<p>On part B2 a)</p>
<p>the force, I assume, is F= (mu)N = (mu) Mg (x/L) </p>
<p>where x is the distance of the bar over the region with friction</p>
<p>so, W = int (F*dx) = int [ (mu) Mg (x/L) dx ] = (mu)MG/L * int [ x dx] </p>
<p>taking the definate integral from x= 0 to x = L I beleive gives</p>
<p>W= (mu)MGL/2</p>
<p>MG(Hcrit) = (mu)MGL/2
Hcrit=(mu)L/2</p>
<p>hmm, thinking back I think I messed up somewhere after taking the integral, :( I better go ask for my solutions and see. </p>
<p>now, what about the time to come to a stop? this one I can't figure out
I keep getting an (mu)g/L *dt^2=dx/x
taking the RHS integral from 0 to L doesn't work, so... can someone point out what's wrong with my reasoning?</p>
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<p>On the mirror problem, yes there may be a vacum above and below the mirror, but the reflection is off the actual (glass?) mirror (n~1.5), so I think there is an additional pi phase shift. </p>
<p>stcoleridge- really? I find the double slit, diffraction grating, and single slit stuff really interesting. In any case you should take a look before you get to QM. It would be hard to tell why an electron beam creates a diffraction pattern if you haven't done light interference first.</p>
<p>Spyder2287- use u=x^2 + b^2, then du=2x dx and the integral works out nicely. In any case it's probably better that you left this unsolved rather than doing it with your 89, because I think they say you aren't supposed to use the algebra system or graphing features of the calc. Not sure how strict they are on this though. </p>
<p>On the circuit one I think by connecting points of equal potential I ended up with 3 in parallel conected in series to 2 and that in series with another 3. From what you guys are describing it sounds like I made a mistake. Again, I should probably get my solutions.</p>
<p>Good luck everyone! I think I'm pretty much out of the running unless the cutoff is like 50% :(</p>