<p>explain how to do these problems ::</p>
<p>Section 2 // #14 & 15
Section 6 // #16 & 18
Section 8 // #12, 14, 15, 16</p>
<p>All the questions can be located at
<a href="http://www.collegeboard.com/prod_downloads/sat/sat-preparation-booklet.pdf%5B/url%5D">http://www.collegeboard.com/prod_downloads/sat/sat-preparation-booklet.pdf</a></p>
<p>I wished there were answer explanations to these booklets :/
Thanks in advance for your help!
*passes out cookies</p>
<p>okay ill help:)</p>
<p>but no. 1… can you please post the answer to the questions next time so i dont have to go back and forth on the pages (its not a big thing, but for future ref. 
)</p>
<p>okay lets begin shall we:</p>
<p>Section 2 // #14:
for this one we know the height the cylinder, the diameter, all we need is the diagonal… all you need to do is pythagorean theorem.
a^2 + b^2 = c^2
(a = height = 5) (b = .5*diameter = radius (because its asking from center of circle) = 2)
so 5^2 + 2^2 = sqrt of 29</p>
<p>section 2// #15
the way i did this one was i simply plugged in squares and added it to 12. if i got a square then it was it.
but i also did another thing. I saw the three options for p - n : 1, 2, 4. we know it cannot be 1 because to get one we need both even and odd (and even + odd does not equal even- so I is out.)
I figured out that two was right by plugging in n = 2, thus p = 4.<br>
so the last question was whether or not p - n was 4. i did not know how to disprove this, but in all the ones i tried, p - n = 4 did not show up. so i was left with B</p>
<p>section 6 // #16
sry i have no idea… i sort of have it… but the process i did is wrong but it gives me the right answer so i dont want you to feel im doing it right and all sry bout this one :)</p>
<p>section 6 // #18
this one is simple (just need a little quick thinking)
if we look at the problem we know two facts the area of the triangle and PT = (2/5)<em>PS
so what if we choose an easy number for PS and go from there
i chose 10 = PS
so if we see our formula PT = (2/5)PS
a little substitution gives us:
PT= (2/5)</em>10
PT = 4
now we got PT, but i want ST (for the base of triangle)
so if we subtract PS from PT we get ST
10-4 = 6
ST = 6
now we go to our area formula!
(1/2)b*h = 7 (the seven is given)
substitute! and solve for h!
(1/2) * 6 *h = 7
3 * h = 7
h = (7/3)
but we are not done, the question wants area of the rectangle so we just use our area of rect. formula!
a = l * w
a = PS * RS
a = (10) * (7/3) and there we go 70/3 or 23.33</p>
<p>Section 8 // #12
the way i solved it was we know that angle z is going to be definitely. larger than angle y. so what i did was i just added all the angles up… x = 20, y = 30: 20+20+30 = 70 (which is the correct answer)./. im not too sure if my method is right, so some one please check!</p>
<p>Section 8 // #14,
so this one is pretty simple, but you need the formula of the arc length:
arc length formula:
(n/360) * 2<em>pi</em>r
where n = angle given</p>
<p>the problem with this problem is we have two circles and the larger circumference, bu no worries away we go!
so lets find the radius of the larger circle
C = 2 * pi * r
36 = 2 * (3.14) * r
r = 5.73
we are told that the smaller circle’s radius is half the larger circle so we divide it by 2
5.73 / 2 = radius of smaller circle = 2.86
now we have the radius, look at the diagram and we see the angle given (80 degrees)
so plug her into the formula!</p>
<p>(80/360) * 2 * pi * 2.86 = arc length
we get 3.9999 and if you round its 4</p>
<p>Section 8 // 15,
haha this one is tricky. i got stumpeld in the beginning. i believe that you chose b as your answer right?
but look more closely at each answer. we are looking for a positive 120 and that is B, D, E.
we know that by day 10, 0 candy bars are left. so E is the right answer the formula is right
120 - (12x) = y
plug in 0 for x, we get 120, plug in 10 for we get 0, this corresponds to the data on the chart!</p>
<p>Section 8 // 16
this is relatively easy, just have to choose right guess choice.
step one) ignore the symbols, they dont mean anything.
it says x = t, so its essentially the same thing. you solve for x, youre solving for t. one and the same.
keep in mind x has to be non-zero. so lets try 1 and -1
we use 1, but the answer is 2 (not an option).
we quickly try -1 and we get -1+ (1/-1)
= -1 - 1
= -2 (an option!
answer is -2 (D)</p>
<p>keep in mind we need to speedly rush through these problems so think, but not too much. especially this last one, yo you can do everything in the brain, but DONT get it wrong :)</p>
<p>hope this helps!!</p>
<ul>
<li>takes cookie offered as a prize, holds it above my head, cookie breaks… wahh!!!*
hahaha</li>
</ul>
<p>I think I know how to solve #16.</p>
<p>It says x < 0, right?</p>
<p>Sometimes, it’s good strategy to plug in a huge value less than zero. Say, -1000.</p>
<p>6 < |x-3| <7</p>
<p>6 < |-1000-3| <7</p>
<p>6 < |-1003| <7</p>
<p>6<1003<7</p>
<p>This is false bigtime. But what this told me was that oh hey, I’d have to pick a number that would fall between 6 and 7 that was negative but reasonable because taking the absolute value of that would HAVE to give me a number between 6 and 7 to make this true. Now all you have to do is prove that the absolute value of some number - 3 will be in between 6 and 7. You KNOW that the values between 6 and 7 are 6.1, 6.2, 6.3, 6.4, 6.5, 6.6, 6.7, 6.8, and 6.9. So, take for instance, -3.1 as x. 6<|-3.1-3|<7 is 6<6.1<7. TRUE. So you can immediately tell that any value you pick between -3.1 and -3.9 and between is going to be an answer. The question said one possible value for |x|, so this just means that this falls between 3<x<4.</p>
<p>CalDud… thanks :)</p>
<p>woot</p>
<p>These problems were tough when I was doing them earlier,
thanks for making it make sense & explaining to me x]
It’s great to have you guys on this forum :DD</p>
<p>no problem! it was good practice for my SAT skills too
thanks for giving me the opportunity to help you with these problems!</p>