<p>
My teacher (AP reader) said that he was that if he came across a problem with a correct solution and an incorrect solution that wasn’t crossed out, the student would receive full credit for their correct solution divided by 2.</p>
<p>Well no, NewAccount, I had the 3 there on the actual test, so it wasn’t wrong (unless I accidentally squared it like I was worried about). I just didn’t see it in his post.</p>
<p>Gotcha. Sorry about that.</p>
<p>Haha no worry, I never said that I had it so your assumption was justified.</p>
<p>Thanks NewAccount…but what if I didn’t have an incorrect solution? Just some random crap that didn’t make sense, and the complete correct solution? Still full points /2?</p>
<p>Oh well, it’s just 1 point, but I was wondering, thank you.</p>
<p>Here’s what I think I got correct:</p>
<ol>
<li>Definitely A, C, and D, maybe B, can’t quite remember</li>
<li>A and C, maybe D, not sure</li>
<li>A, B, and D, now that I think of it I think I screwed up on C</li>
<li>No doubt on A and B, possibly C</li>
<li>A, and parts of B, and got prolly 1 point for C</li>
<li>Nothing :(</li>
</ol>
<p>So I’m thinking somewhere around a 25-30 or so on the MC. Not great, but I’ll definitely get a 3, if not a low 4.</p>
<p>RC1992, to get a 4, you only need to get about 45 points.
so if you get 30 on mc, 30*12 = 36.
And only 10 points from FR is enough to get a 4.</p>
<p>Hmm, I think I did pretty well overall (can’t remember all my answers), but I forgot to check endpoints, so I got the 9.813 answer or whatever 
Weird…I usually remember to check endpoints! Hopefully I can still get my 5…we’ll see, but whatever; I can still get credit for a 4. It’s more of a personal satisfaction thing :D</p>
<p>Can anyone confirm what webass said? 45/108 seems kinda low for a 4…only about 42%…</p>
<ol>
<li> 0-24
<ol>
<li>25-39</li>
<li>40-54</li>
<li>55-69</li>
<li>70-108</li>
</ol></li>
</ol>
<p>That’s the usual scoring…
I’ve posted this before, but it’s fun playing around with numbers when you get bored…
[AP</a> Pass - AP Calculus Calculator](<a href=“http://appass.com/calculators/calculus]AP”>http://appass.com/calculators/calculus)</p>
<p>for 3d, is the answer</p>
<p>700 + ∫(0→t)r(t)dt = 800(t)</p>
<p>whats the answer for 2b?? I got 21. somthing</p>
<p>isnt the formula 1/8 * (b-a/n) * ((0+4) + 3/2*(4+13) + (13+21) + (21+23)/2)</p>
<p>and where b-a/n == 8/4 = 1/2 ???</p>
<p>user, I think so, I think that’s correct. Except, if you used different variables, would it still be correct? </p>
<p>ber1023, I posed the complete solution to number 2 on page 7 of this thread. And yes, 2b answer = 21.375
EDIT: lol ber, you looked at my solution yesterday and said it was all correct -_-</p>
<p>Could someone pleaseeee post the complete solution to #3? thanks!!</p>
<p>yeah i said it was correct, well based on what i thought. However i wasn’t sure bout that b-a/n in the front and wasn’t sure if it was suppose to be there! </p>
<p>i think the previous posts about number 3 were correct</p>
<p>i just put a thread up … <a href=“Conditional Offer question!! - Applying to College - College Confidential Forums”>Conditional Offer question!! - Applying to College - College Confidential Forums; … if you could answer my query that would be great im a lil worried</p>
<p>also for number 2 it says E(t) is the number in the box at time t. But in B it says to intergrate E(t), that doesn’t make sense?</p>
<p>can anyone really explain the justification for 6B to me??</p>
<p>because y’’ is > 0 so its concave up, therefor the tangennt line is below so its under</p>
<p>Ber, on 2B you’re integrating, and then multiplying by 1/8, AKA you’re integrating and dividing by the interval, AKA finding the average value.</p>
<p>yes but it says in the question that E(t) is the number in the box at time t, so if its the average number in the boz its 2300/8 ? the question should say its the number put in the box per hour, as in the rate</p>
<p>2300/8 would be assuming the entries were put into the box at a constant rate. Part B is the definition of the MVT for integrals. If it had given you an equation that modeled the table, you would take the integral of the equation and divide by 8 to find the average value.</p>