<p>Finally, it has been over 48 hours. </p>
<p>Does anyone still remember the order & answers to the free response? Post them here.</p>
<p>the first question had to do with areas of R and S. the answers were decimals. </p>
<p>For the slope field, i got f(x) = (3 - 2x^2)^.5. not sure exactly if that was it. i also got -.8 for the estimated value. y=2x+3, something like that. </p>
<p>i got 75.625 for average temp.</p>
<p>i ended up with 2487. for the total sand left. </p>
<p>inflection at x = 2 for the second fundamental theorem question. </p>
<p>average rate of change = -5/6
360 meters for total distance traveled</p>
<p>i update more later, go to go to class.</p>
<p>I remember that the volume of revolution answer was like 5.something</p>
<p>I agree with the -.8 for the predicted one.
I agree with the x=2 for pt. of inflection.</p>
<p>I don't agree with the avg. temp. I remember getting like 67.something degrees.</p>
<p>The other two i can't remember.</p>
<p>I got .065 for area of R
.410 for area of S
and 4.559 for Volume
I used a calc program to find the volume so I had NO work for it</p>
<p>Stupid me did a regression equation from that chart on the temp. So I prob got it all wrong</p>
<p>Yeah 4.something.</p>
<p>I agree with you BCgoUSC for all of those.</p>
<p>Do you think they'll give me partial credit for the Volume
All I did was draw the picture, write Washer Method and write the answer
Could I possibly get partial credit for the temp one?
I'm a BC Calc. person though</p>
<p>I got the same answers for the volume and area. I also got 75.625 for the average temperature.</p>
<p>i got 2492 for total sand left, but i rushed it</p>
<p>on the piecewise graph question- the Mean Value Theorem does not apply, because it the MVT requires that the function be differentiable, and this graph had a cusp</p>
<p>I also got 75.6something for average temp
And I agree with mattistotle about 2492 for total sand</p>
<p>for the slope field...was the equation (-2x^2 + 3)^0.5 or -(-2x^2 + 3)^0.5? because they said f(1) = -1 and the only way that would happen is if that equation is negative. so i don't know...</p>
<p>i agree with shoo-shakin ... the square root must have a neg sign in front of it</p>
<p>wow i mustve totally screwed up the slope field one, i got e^x2 + 1</p>
<p>took the integration and set ln y = x^2</p>
<p>thats how my teacher told us to handle those kinda problems, guess it was wrong lol</p>
<p>how were you suppose to do question number 3, i wasnt sure about that one</p>
<p>what was question number 3 again?</p>
<p>mattistotle I agree with you on that slope field one. I got e^-x^2 or something too. I remember it was the only one that made sense. MC right? I think they are talking about something else.</p>
<p>and for the slope field...all you had to do was separation of variables, solving for C and then plugging it back into the equation.</p>
<p>for the area of s, u just had to find the point of intersection and subtract the curves right?</p>
<p>and for the volume when revolved about y=-1, it was just (1+curve)^2-(1+curve) right?</p>
<p>and for the slope fields one, how did u guys get a e^x, cuz after u separated variables, didn't u get integral ydy on the left side??</p>
<p>ahh screw it only going for a 3</p>
<p>Wasn't there a question on the sand free-response question asking about what the rate of change of sand on the beach was? And what part asked about how much sand was left? I thought the question was more like how much sand had been added during the first # hours or something.</p>
<p>I have the free response section. My teacher gave it back to us today. I was so sure I had number 1 but I messed up on the volume one becuase instead of adding -1 I subtracted it so I got half of what I should have.</p>
<p>Here's the sand questions</p>
<p>sand removed at a rate R(t)=2+5sin(4tpi/25)
sand added at a rate S(t)=15t/(1+3)
units cubic yards per hour and t is hours from 0 to 6. At t=0 there are 2500 cubic yards of sand
a)how much sand will the tide remove from the beach during the 6 hour period?Indicate units of measure.31.816 cubic yards
b)write and expression for Y(t), the total number of cubic yards of sand on the beach at time t. 2500+(fnInt(15t/(1+3t))-fnInt(2+5sin(4tpi/25)))
c)find the rate at which the total amount of sand on the beach is changing at time t=4*I can't remember what I put*
d)for 0<=t<=6 at what time t is the amount of sand on the beach a minimum? what its the minimum value? Justify*I said t=0 and 2500 cubic yards but I think its totally wrong and it should be something like t=5.???*
Bold is what I got for my answers.</p>
<p>yeah it was like t = 5.118 or something like that. don't remember exactly.</p>