<p>i also got one…</p>
<p>but many people said 2 .</p>
<p>= =</p>
<p>Cause the way I remember it said how many inches should overlap… and i said one because the overlapping part is only 1</p>
<p>^
It’s 2. We’ve already established this</p>
<p>what page?</p>
<p>waht is the right answer for 35 products?</p>
<p>Just to repeat:
Each string (was it string?) is 6in long and there are 5 of them, making a total of 30 inches if they are laid out end to end. The question asks how much string overlaps if the total length is shortened to 22 in. Looking at the diagram, you see that there are 4 overlaps (between five strings). (30-22)/4 = 8/4 = 2in.</p>
<p>the answer was def 2. ppl who put probs thought that since two pipes touch at each overlap you have to divide your answer by 2 and get one and that way but thats not how it works. When the overlap is 2 it comes out to be 4+2+2+2+2+2+2+2+4=24 with the ends pipes as 4 each and the overlaps at 2 each and the middle pipes at 2 each. i thought that it was one at first too. hopefully that helped. and i could swear that the caffeine one went from greatest to least … ■■■</p>
<p>I find that the overlap problem is easiest to do with a picture, but we don’t really have that here, now do we? :P</p>
<p>So basically, it starts as 30 inches (or whatever) long. The overlaps make it go to 22. That’s a difference of 8. There are 4 overlaps, so 8/4 = 2. Therefore each overlap is 2 inches long.</p>
<p>Some people say you have to further divide that by 2 because there are two sticks in each overlap, but that’s incorrect. To show this, think about the stick on the far left. You keep it where it is, and move the stick directly to its right to the left two inches. Basically, you kept the length of one stick and just cut 2 inches off of another. It doesn’t affect the length of both sticks.</p>
<p>Sorry, that’s really as clearly as I can word it, but it doesn’t seem very clear. Haha.</p>
<p>the answer is definitely 50/51. Use your calculator to double check using the sequence button and sum button under lists.</p>
<p>Can someone confirm whether or not the question with 1/4095 (or something similar) as an answer was part of the experimental math section? Because I had a writing experimental but I don’t remember having a question with that at all.</p>
<p>I did not have a question with 1/4095 as an option…</p>
<p>^^I just added up the three numbers that were presented ((1/2), (1/6), and (1/12)) to get (3/4). There were three numbers in the sequence thus far, so I noticed that the sum is N/(N+1). After doing this with the next number in the sequence and finding that it held true, I marked 50/51 as the answer.</p>
<p>@OSUBuckeyes
Okay good. Then what’s with all the talk about some question with 1/4095 as an answer a few pages back?! Scared me. I thought I skipped a problem or something.</p>
<p>It could be an experimental question, no?</p>
<p>To clarify, the knitting question was the exp math section correct? If so I have a few questions. How do you do that problem and what were some of the harder problems in that section?</p>
<p>Let me just pose this simply. Did you receive a math question that had to to with knitting and and inequality with b.</p>
<p>was one of the free response answers 4/3?</p>
<p>I had no knitting question and an extra reading section, so it must’ve been variable. Math wasn’t hard, but time is my demon. The math in fact is usually 150 points lower than my other two sections. I really regretted being unable to answer the sum of the series question after having been so good at it in my math class last year. the free response was easy, and the first two or three questions of every math section I swear a 3rd grader could do. The graph questions also tripped me up because of time.</p>
<p>yea the first math questions are always a joke… did you get 4/3 on any free response or was it 1/3?</p>
<p>Also there was a graph problem and the answers were either 5200 or 5700. To me it looked like 5450. I picked the former.</p>
<p>I picked 5,700. It looked about 5,500, so I just went to the closest one.</p>