<p>Thank You, but can you explain your thought process when doing this question? Like did you have a formulaic way of thinking or did you just divide one by one?</p>
<p>Try the method called “picking numbers.” That’s what I did. Poster #2 kind of has it backwards, but basically correct. Divide 15 by 4 and you get 3 wholes and remainder 3. Divide 15 by 6 and you get 2 wholes and a remainder of 3.</p>
<p>^Realizing that the divisor has to be a factor of 12 is helpful, but only if you also realize that you don’t need to check any number smaller than 4 – a remainder is always less than the divisor. If you don’t realize that, you might include 2 and 3 since they are both factors of 12. But if you check 2 and 3, you see that they don’t give the desired remainder.</p>
<p>Still, if none of these insights occur to you, you can get the right answer just by carefully checking the divisors from 1 thru 15…doesn’t take that long either way.</p>
<p>(@gcf101 – i see that you specified k>3 – others might miss that!)</p>