ACT Geometry help, and ACT vs. SAT?

Test Preparation ACT Preparation
1

<p>Firstly ACT vs. SAT:
If I take the ACT, do I have to take the SAT? Could I just take the ACT and two SAT subject tests? (I've taken a practice SAT but I feel more comfortable with the ACT; 2050 [730W, 720CR, 600M] compared to 32.) Would most colleges accept the ACT?</p>

<p>Secondly, could someone help me with ACT Geometry, please?
On the practice, I got 33 W, 33 CR, 34 Sc, and 28 M. I was fine with the algebra, but got almost half of the total geometry wrong. I know SOHCAHTOA, the sinA/a = sinB/b, congruent triangles, and alternate, corresponding, and supplementary angles, but I don't always know how to apply them.</p>

<p>Specifically these questions on the practice exam:

<a href="http://i48.tinypic.com/2vulriq.png%5B/img%5D"&gt;http://i48.tinypic.com/2vulriq.png

</a>
(I've worked out 38, 42 and 57 now, it's just the others. They are 18, 58, 59 on <a href="http://media.act.org/documents/preparing.pdf%5B/url%5D"&gt;http://media.act.org/documents/preparing.pdf&lt;/a> if you don't want to view the image. Two are algebra, but I don't understand how you can take away the "n" on 59. Do you need to complete the square or something?)</p>

<p>Thank you. :) Any good books or websites about ACT math would be appreciated.</p>

<p>Would I be able to improve math before the April ACT? Do you think an overall composite of 34 would be possible if I improve on all 4 areas?</p>

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<p>Most colleges accept either the ACT or SAT (in addition with SAT subject tests, if required). Assuming your other scores are constant, you’ll need around a 33-34 to get a 34 composite.</p>

<ol>
<li><p>Just draw a circle and label the points. First pick a point for A, then label the other three. Read carefully (don’t mix up counterclockwise, clockwise). You should get A,C,D,B, (J).</p></li>
<li><p>Let a<em>1, a</em>1 + n, a_1 + 2n be the sequence (n is the common difference) with</p></li>
</ol>

<p>a<em>1 + 5n = 8
a</em>1 + 9n = 13</p>

<p>Solving the system yields a<em>1 = 7/4, n = 5/4. The sum of the first four terms is a</em>1 + (a<em>1 + n) + … + (a</em>1 + 3n) = 4a_1 + 6n = 4(7/4) + 6(5/4) = 14.5, (G).</p>

<ol>
<li>Since -3 is the only root, the quadratic x^2 + mx + n <em>must</em> equal (x+3)(x+3), or x^2 + 6x + 9. Therefore m = 6, (C).</li>
</ol>

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<p>Thank you for the help. :)</p>

<p>I’ll look back on arithmetic sequences, and thanks for the advice on factorizing in 59.</p>

<p>I’ll take another practice ACT math test and keep this in mind… hoping for a 30 this time.</p>