<p>@xavier, the answer was not 115; it was 116, because it mentioned that it had to be “one above the standard deviation”</p>
<p>for the absolute value question how was the answer B? Wasn’t the question like find the domain of the inequality |1-x| < B? (I feel like I am possibly mixing up the order of 1 and x and the less than sign) Regardless, wouldn’t the equations have to have the inequality sign in the same dirrection? i.e. 1-x < B and x-1 < B – wouldn’t you flip the sign for one of them only if you were solving for x which was not done in the answers?</p>
<p>Edit: Ah, okay I see what I did wrong Rival’s math seems right.</p>
<p>And the last three were F,A,F right? </p>
<p>the last one was not F because F would be the first choice.
The last one was the fourth one. So it was D or something else that was fourth down.</p>
<ol>
<li>It was a Pythagorean triple.</li>
</ol>
<p>Edit: Never mind. That was the answer to a different question. The one below me is correct.</p>
<p>The answer was A) 85 east like 181 north</p>
<p>@michlove </p>
<p>sin(25) * 200
cos(25) * 200</p>
<p>were the two answers.</p>
<p>I’m pretty sure the question was: if point (a,b) is symmetrical with the y axis and one other point, what would that point be? Something along those lines. I put (-a,b) though, whatever the question actually was.</p>
<p>@Ivysaur: I thought the question was phrased: your score has to be at least one standard deviant above the mean in order to pass the class. In that case, I put 115.</p>
<p>The answer was 115. It said one standard deviation above the mean, not one above the standard deviation.</p>
<p>I also put down 115. I thought about it long and hard to and make sure I read the question right…</p>
<p>@RivalDestiny: Same here, I hate it when a question seems too easy and I end up rereading 5 or 6 times :P</p>
<p>isnt the answer (a, -b)</p>
<p>…because if its symmetric with respect to the y-axis… it should reflect over the y-axis and then wouldn’t the x coordinate stay the same and the y coordinate just be the opposite? i envisioned the square root graph (with both halves)</p>
<p>^no (a,-b) is symmetric with the x-axis. not the y-axis.</p>
<p>nritya: What you’re describing would be a flip over the X-axis, not the Y. It is the opposite of what you are thinking.</p>
<p>for the standard deviation one, i put 115. it said it had to be AT LEAST 15 above. i hope that’s right</p>
<p>@nritya</p>
<p>drawing an image helps.</p>
<p>■■■</p>
<p>10 char</p>
<p>@nritya: Think about the graph y=x^2, a parabola which is symmetrical with respect to the y-axis. Any point on the graph other than the vertex will have one corresponding point with same y-coordinate but opposite x-coordinate. So the answer would be (-a. b)</p>
<p>yeah you’re right. ARGH i remember thinking to myself, “okay don’t make any stupid mistakes, this is really easy” and BAM, i made a stupid mistake.</p>
<p>yeah…so far I know I missed the last question and also I put 12,000 for the one with the shaded region when thinking about it now I know it was a bigger answer than that. I’m thinking -4 on the math for me…</p>