ahh math review I can't get

<p>this is kinda pathetic, but i can’t do some of the questions on my math review. if you can do any of them please post.</p>

<li><p>A neighborhood of -4 with radius 2 is describe by
a. abs value(x-4) less than or equal to 2
b.abs value(x-4) < 2
c. abs value(x-2) <4
d. abs value (x) <2
e. abs value (x+4)<2</p></li>
<li><p>if 6x^7 - ax^5 +bx^3 - cx - 15 = 0, where a, b, c are integers, which of the following could not be a root of the polynomial equation?
a. 3/2
b. 3/4
c. 1/6
d. 5/3
e -15</p></li>
<li><p>1/(1 +sinx) + 1/(1 -sinx) =
a. 1/(1-sin^2(x))
b 2 sec^2(x)
c. cos x
d. tan^2(x)
e. csc^2(x)</p></li>
<li><p>the graph of abs value(y) = abs value(x) is
a. a circle
b. a line
c. two intersecting lines
d. a hyperbola
e. a single point</p></li>
<li><p>If f(x) = x^5 +x^3 + 1 and f(a) = 10, then f(-a) =
a. -7
b. 10
c. -10
d. 8
e. -8</p></li>
</ol>

<p>ahh sorry thats 5 i can’t do, thanks a lot if you will help me out</p>

<p>1) b
x=-4 with a radius of 2 which gives -6<x<-2
4) b
+/-p / +/-q = +/- 15,1,5,3 / +- 6,1,3,2 which gives
+/- 15,1,5,3,15/6,15/2,1/6,1/3,1/2,5/6,5/3,5/2,3/2
5)b
get common denominator and add
((1-sinx)+ (1+sinx))/ ((1+sinx)(1-sinx)) = 2/(1-sin^2x) = 2/cos^2x
or 2 sec^2x
6) C
l y l = l x l<br>
14) E
a^5 + a^3 + 1 = 10 ; (-a)^5) + (-a)^3 + 1 = ?
a^5 + a^3 = 9 ; -a^5 + -a^3 + 1 = ?
-(9) + 1 = -8</p>