<p>im not good at finding all the roots and squares to type them out so excuse my technophobity ( is that a word?) :) </p>
<ul>
<li>square root of (x^2 - t^2) = 2t-x </li>
</ul>
<p>if x and t are positive numbers that satisfy the equation above, what is the value of x/t ??</p>
<p>well,another math question,let's see...
* square root of (x^2 - t^2) = 2t-x
<=>(x^2 - t^2)=(2t-x)^2
<=>x^2 -t^2=4t^2 - 4tx + x^2
<=>5t^2 = -4tx
because t>0,so
<=>5t=-4x
<=> x/t = -5/4
hope it's rite :-)</p>
<p>sorry tee8tee its not correct thats exactly what i did i dunno what else to do ? i'll give u the correct answer maybe u'll figure it out and inform me
its *28/5 * i dunno where they got the 28 from but thats the correct answer!
hope someone can figure out how its solved !
thanx anywayz</p>
<p>oooh shoot thats the correct answer i must have been looking elsewhere
thanx and sorry!! :)</p>
<p>Phew,u make me nervous!Anyway,I'm willing to answer any math problems you dunno</p>
<p>Just wondering how - 5/4 is the answer when it says that x and t are positive numbers?</p>
<p><=>(x^2 - t^2)=(2t-x)^2
<=>x^2 -t^2=4t^2 - 4tx + x^2
<=>5t^2 = 4tx
because t>0,so
<=>5t=4x
<=> x/t = 5/4
Sorry,how stupid I'm.That's correct one.</p>