<p>I'm surprised we don't already have one of these threads.</p>
<p>So it's in two days.
Who's ready? </p>
<p>I find the Free-Response Scoring Guidelines by CB completely obscure as they don't fully explain their solutions . . .</p>
<p>That’s because everyone’s too busy cramming for CSAP.</p>
<p>Question: Are there any resources online where I can learn series, polars, and vectors? My teacher rushed through those topics in about a week and he didn’t cover them well at all (he was great for everything else though!).</p>
<p>Luckily the curve is VERY forgiving.</p>
<p>Ohh true, ouch.
I don’t even know Polars/Parametrics/Series. . .
I’m hoping to learn it by going through all the past Free-Response questions!
There might be something on the CB’s Calc BC page though?</p>
<p>Could anyone help me out with <a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board; 3.c)? I don’t understand why they did that/where they got those numbers.</p>
<p>@Abrayo: The first term (1) is from 0 to 1 on the y-axis. The second term looks like distance formula for the straight line. The third term seems to be the calculation for length of a curve.</p>
<p>This is just from cursory inspection, so I’m not sure if that’s what you were looking for or if you wanted a more in-depth response.</p>
<p>That was about what I wanted.
I see how they got the 1.940 (the point of intersection between the two curves) but not sure where they got 1.455.</p>
<p>And for the formula for the length of a curve:
Is the formula always the square root of 1+the derivative squared?</p>
<p>Well, the straight line says y = 3/4 x, so the y-coordinate would be 3/4 times 1.940 = 1.455. Then you use the distance formula to find the length of the segment to that point.</p>
<p>Yes, it’s always the integral from A to B of sqrt(1 + (dy/dx)^2) dx.</p>
<p>I understand, thanks!</p>
<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
<p>Question 6. c) and d).
What is “AST”? Did they know that by comparison or something? (specifically in part D, am I supposed to know that 1/n^p diverges for p <= 1, etc?)
And aren’t the two intervals in c) basically the same thing . . . besides the 0< part.
Same with d). Why are the domain’s pretty much the same, except for the lower/higher bound?</p>
<p>AST is the Alternating Series Test. Basically, an alternating series converges if a) the limit as n approaches infinity of the sequence “a(n)” is zero, and b) a(n+1) <= a(n) meaning the terms are equal or decreasing.</p>
<p>The p stuff is the p-series test. You stated it yourself: 1/n^p diverges for p <= 1 and converges for p > 1. Remember that although the series 1/n diverges by the p-series test, the alternating version [(-1)^n]/n converges by the AST.</p>
<p>I think on c) and d), they expect you to give a specific value of p, like p = 1/4, and then support your answer by stating the intervals of p for which the series would converge.</p>
<p>Hope that answers your questions!</p>
<p>It does!</p>
<p>However, I still don’t understand how they got that range of 0<p<= (1/2). [this is in part c).]
How would p value of 1/2 make it a) zero or b) all the terms equal or decreasing? Would it make them alternate in sign because of the (-1)^p and thus every other one would be bigger than the other?</p>
<p>So I would just say “a value of p = 1/3 because, by the AST, it converges.”?</p>
<p>For whoever asked about polars/parametrics, these websites are good at teaching and explaining stuff:
[Visual</a> Calculus](<a href=“http://archives.math.utk.edu/visual.calculus/index.html]Visual”>http://archives.math.utk.edu/visual.calculus/index.html)
[Pauls</a> Online Notes : Calculus II](<a href=“http://tutorial.math.lamar.edu/Classes/CalcII/CalcII.aspx]Pauls”>http://tutorial.math.lamar.edu/Classes/CalcII/CalcII.aspx)</p>
<p>meh. I don’t know polars at all either…</p>
<p>Does anyone know how big a portion of the test will be about that? a full FRQ?</p>
<p>There is often a full FRQ on either parametric or polar. Since last year was parametric, I’m guessing there will be a polar question this year. There might be a few multiple choice on parametric/polar too.</p>
<p>Does anyone know the scoring guidelines for 1,2,3,4 or 5? My teacher has never given us any practice tests so I haven’t a clue.</p>
<p>Thanks for the links, CORVIDS!</p>
<p>Fantastic . . . gotta cram in polar as well.
For parametrics, all that can really be tested is finding like, average speed/positions, right?
That’s all I remember from doing FR questions so far. Are there any tricky concepts?</p>
<p>@thesos76:
<a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;
That was updated to reflect the no deductions, I believe. So about 63%?
That’s pretty low, isn’t it?</p>
<hr>
<p>Are part marks given for wrong answers used later on? I know it works for some other exams (Chemistry, for example) but in the marking rubrics it never says anything like “point for using an incorrect value from a previous part” or anything . . .</p>
<p>Guys, isn’t the integral of 1/whatever ln (whatever), in most cases?
Why doesn’t this work for 1/sqrtx? Why is it 2sqrtx instead of ln (sqrtx)?
I understand why it works for 2sqrtx but I don’t understand why the ln (sqrtx) doesn’t work.</p>
<p>Integral of du/u =ln|u| but in the case of dx/sqrt(x) You have to do u substitution if you want it in the du/u form. Thus u = sqrt(x) du=dx/[2(sqrt(x)] </p>
<p>And you get Integral of 2sqrt(x)du/u which isn’t in the form of du/u thus you cannot use du/u = ln|u| rule</p>
<p>Hopefully that makes sense.</p>
<p>I am so screwed for this exam! I got a 4 on the Calc AB exam as a junior but now I’m totally freaking out.</p>
<p>One more day…how is everyone feeling?</p>
<p>lets do a survey of whose feeling good and whose feeling bad.</p>
<p>GOOD -
BAD 1</p>
<p>Do you guys have any predictions of the FRQs? I’m pretty sure there will be a volume one and polynomials.</p>