Do you guys think the curve for a five will be substantially higher this year compared to last year?
@Kitsyxoxo i doubt it, it will probably stay around the same considering the difficulty of the inactive mc and the funnel which will probably have low scores
What was the cutoff last year for a five?
bro, on the first one, is 950-1190/2=-120…
furthermore, on 1) iv. consider endpoint and ivt. This is a common miss in our school as well. let h(t)=W(t)-R(t). h(0) is greater than 0 and h(8) is less than zero, and since both W and R are continuous, so is h(t). Thus by IVT, there must be a value c, btw 0 and 8, such that h©=0, implying W©=R©
you are correct, the answer should be less that 1. He did dx/dy instead of dy/dx
Yea wait how much out of 108 will I’ve you a 5?
4d) shoud be less than the original value since the dervative is negative at h(0) and h(0.5)
5c) recognize chain rule. dh/dt = dh/drdr/dt
directly differentiate respect to r. then the equation becomes 1=2h/20dh/dr
at h=3, dh/dr= 20/23=10/3 dh/dr. Thus at h=3, dh/dt=10/3-1/5=-2/3
sorry i misread what you said. Your #4 is completetly correct and should worth 8 pts or more, depended on how many little errors you make.
yes it does The derivative exists means that g(x) is continuous at that point which by extreme value theorem, has max and min
One thing that i want to point out is that for 3c, i am very confident that more than 70 percent of the test takers are going to miss points. Remember endpoints have to be checked as well as critical points. This typle of question appears in past tests numerous time and the statistic shows similar ratio of missed. If you did not check both g(-2) and g(12), there are probably points being deducted.
@Kitsyxoxo I can’t remember who it was on this thread but someone mentioned that last year 63/108 was sufficient for a 5, which is only ~58% of the test
So for the dreaded funnel question: to find the volume I took the following steps:
Realize there are circular cross sections. This means we plug in the circular formula. We can also pull out the 1/20 if we square it. this means we have 1/20 * 1/4 * pi int (r w/o 1/20)^2. Doing this I came to an answer of 109,020pi / 1600 equaling about 214. Does then seem somewhat / partially right to anyone?
I know i butchered the actual arithmetic but I’m hoping for at least 1/2 credit here.
Does anyone know if the May 5th students are compared (scale-wise) with the kids who take the AP Calc test May 19th? Because I think it would be pretty unfair because they got more time to study and they now know the questions. I mean I’m sure this won’t affect them tremendously but I’m sure there are schools out there where kids already know all the MC that was on the test. Which according to my teacher, doesn’t change??? Even on collegeboard website it says only half of the exams given will be new and the other half old. I don’t know. I’m just upset that I didn’t do so well and it would suck if my score was on the same scale as the kids who get to take it later.
The students taking it on May 19th get a different form.
I think i got a 5 
Most of my answers match up with pepole’s solutions on this thread.
Pretty fair test. Tough no Calc MCQ, smooth sailing all the way until #6 on the FRQ. Hopeful for a 5
when do the scoring guidelines get released?