<p>You take 257.1 g of a solid at 30.0oC and let it melt in 400. g of water. The water temperature decreases from 85.1oC to 30.0oC. Calculate the heat of fusion of this solid</p>
<p>Q of water + Q of solid = 0
so mass of water * specific heat of water * change in temp of water + DHfus =0</p>
<p>You solve for DHfus.</p>
<p>yeah i tried that bu i cant get that
the answer is supposed to be 358</p>
<p>bump<br>
bump<br>
bump</p>
<p>heat absorbed by solid = mc (delta T) = (0.400 kg)(55.1 deg C)(4.19 kJ/deg C.kg) = 92.3 kJ
since heat absorbed by solid = heat required to melt 0.2571 kg of solid,
Lf = 92.3 kJ/0.2571 kg = 359 kJ/ kg = 359 J/g</p>