<p>Oh okay thanks. Is that scoring worksheet based off of last years curve?</p>
<p>@asianandproud: I’d guess a low 4 based on what you said. Easy 4 if you got 55 on MC.</p>
<p>I consider 55 and higher on MC on pace for a 5. That means the student needs to get about 60% of the FRQs to get a 5.</p>
<p>I realistically got about 50 MC questions probably maybe a little lower, like 48. Most probably 50. I did end up guessing on some, but I knew a lot too.</p>
<p>MC: 45/75
FR1: 1/9
FR2: 4/10
FR3: 6/9
FR4: 3/15
FR5: 6/9
FR6: 6/8</p>
<p>= 80.1034 = 3</p>
<p>This is a bit worse than what I expect so I think it’s pretty likely i got a 4!!</p>
<p>I’m sort of expecting a 4 too, if I don’t get it, I’ll probably have to take it again next year ;(</p>
<p>do you think I could explain why it’s a weak acid because “pH=pKa at half equivalence bla bla bla showed the Ka value which was pretty small and said the Ka of a strong acid would be much greater” ??? D: D: D: D: D: D:</p>
<p>@808wawa: That will probably be accepted.</p>
<p>Lol thanks hypnotoad XP</p>
<p>What about if I said that the pH, which was calculated in the later part of the problem, was too high of a pH for it to be a strong acid, so it must be weak?</p>
<p>I think I got a 2 or 3.
I’m so sad right now.</p>
<p>Anyone here have a compiled list of curves from released exams?</p>
<p>Umm I have question for number 5 eii)? Since all ionic bonds are polar, could you say that KI dissociates in water since the polarity of h2o causes the KI bond to break into two ions in which I- would react with the undissolved i2 solid.</p>
<p>My response for #5 eii: ALL IONIC BONDS R POLAR! KI dissolves in H2O because the polarity of H2O causes KI to break into two ions-K+ and I-. Since there is still undissolved I2 present from the part d, the foLlowing reaction occurs.
I2 + I- => I3-
this reaction cannot occur in hexane because KI doesn’t dissolve in it due to KI being polar and hexane being nonpolar…
Wouldn’t this make more sense than the other answers Ive been hearing…?</p>