Oh, I though it was attached.
O god had form E MC was literally cancer holy. FRQ’s seemed simpler except for the last 2 which I had some trouble with.
Is there a google doc?
Google Docs aren’t allowed and I don’t think people make docs for AP tests do they /?
@MileSwimmerDude Did you get zero velocity in the y direction for the pulse problem? and constant velocity in the x direction?
@Devanche12 I wasnt sure on the wave pulse problem. I did put constant X velocity, but for y velocity I put there would be a constant velocity positive, constant, then negative as the wave moved across point P. It didnt make sense to me that there would be no y velocity if it is moving up and down.
@MileSwimmerDude Oh okay… and what about the one that was asking about the new wave pulse? Did you say that it would travel faster because of increased frequency? Did you say it would travel faster at all? And the hemispherical bowl problem at the end… I said the height would be exactly where it was initially because of conservation of energy but others say no because the bowl can move… what did you put and was I wrong?
@MileSwimmerDude what did you get for part d of the spring experiment problem and how did you do the experiment? Also what did you Form C people think of the MC?
I think the frq was pretty easy except for the one where it was a spring and -D that went to 3D. That doesn’t make sense to me because if you pull it back D shouldn’t it go D distance after the equilibrium too? Also how did you calculate the distance it traveled if it was pulled back double?
i got 12D for that one
used conservation of energy and then put the velocity into kinematics equation (the acceleration is (miu)(g))
If you thought that your AP test was stressful, my testing center was hit by a tornado… 
@pigscanfly1324 yeah I said that too, but I just mentioned that doubling the compression of the spring would increase the potential energy by a factor of 4, leading to the distance traveled being quadrupled as well.
Yo this test was easy
That circuit frq was pretty hard
@Devanche12 I said that yes it would travel faster, but I asked my AP Physics teacher today about it and she said that it wouldnt have changed the speed, and she gave me some really confusing reason why not, so I am not sure…I put that it would reach the same height on the other side because there was no friction. Some people were probably trying to prove it wont but in reality it was a pretty simple problem. The semicircular ‘ramp’ was attached to the ground I thought. I think we are right. @shizpie I allowed the cart attached to the spring to oscillate when the spring had one end attached to a solid chair leg that wouldnt move and the other attached to the cart. I placed the motion detector past the cart so I could measure its velocity at its fastest point. Then I stated later we could use 1/2mv^2=1/2Cx^2 to find the value of C.
@MileSwimmerDude for the cart problem I said that we can hold it some x distance past equilibrium point then use the motion detector to plot a velocity time graph once it was released from rest. We would continue to do this 4 more times with 4 different stretch distances, thus giving us 4 different velocity time graphs. Taking the average velocity, we could plot momentum as a function of time by multiplying by the cart mass, take the slope of that to get force, then take the slope of a force - stretch distance graph to get spring constant, and the area under that graph would give us energy. Would that work?
@Devanche12 Your procedure/lab sounds very involved, and they will love that. But no matter how far you stretch the spring from equilibrium it will oscillate at (I believe) at one fixed amplitude; so you didnt need to do four trials. For the labs they mainly just want to see your procedure so the different trials are sort of wordy and trivial. Your procedure of using the graphs to find each value seems sound, but I simply weighed the cart on a scale and used F=kx (not sure if I was allowed to) to find out the theoretical K value. Additionally, I think in the lab intro they stated the motion sensor could only graph acceleration, velocity and position as functions of time. They wont deduct points for your experiment being lengthy, so i would expect you will receive a pretty high score on the lab. good job 
@MileSwimmerDude Some people said that for trial 1 and trial 2 for the pencil FRQ they would have an equal length of smear because of the arc length of each would be the same… is that true? I said that trial 1 would have a longer arc length because it takes more time to stop but then again because its closer to the axis of rotation (the center) it would have a smaller circumference…
@Devanche12 That problem was VERY tricky. The angle would be the same, but trial 2 would cover a larger distance because it had a larger radius. Think of it like two different circles within the disk. I may be wrong, but that is how I conceptualized it. The angular velocity and acceleration, remember, are the same NO MATTER what point it is at on the disk. For this reason, I stated that it’s time would be the same (with the angle and angular velocity the same, T must be the same), and that trial 2 would have a larger/longer smear. My teacher mentioned torque as being an issue, but I do not think it applies here (although it might). This was one of the questions I’ve struggled with, and a few of my friends got both contradicting and the same answers that I got.
@MileSwimmerDude So you said trial one and trial 2 would stop at the same time and trial 2 would have a longer smear? oh no… i said trial 2 takes less time to stop and that trial 1 has a longer smear… oh god