<li><p>A particle travels in a circular path of radius 4 m at constant speed. The net force on the particle is 60 N. The kinetic enregy of the particle is
(A) 40 J
(B) 60 J
(C) 120 J
(D) 140 J
(E) Cannot be determined from the given information.</p></li>
<li><p>An object with a mass of 5 kg is attached to a 1 meter long rope and whirled in a vertical circle. At the bottom of its path, the rope has a tension of 95 N. The object is moving most nearly
(A) 2 m/s
(B) 3 m/s
(C) 6 m/s
(D) 9 m/s
(E) 15 m/s</p></li>
<li><p>What is the maximum speed a vehicle can travel along a circular turn without leaving the road? The turn has a radius of 50 m. The road has a coefficient of kinetic friction of .20.
(A) 5 m/s
(B) 10 m/s
(C) 15 m/s
(D) 20 m/s
(E) 25 m/s</p></li>
<li><p>A 10 kg object moving in a horizontal circle of radius 5 m experiences a centripetal force of 50 N. What is the velocity of the object?
(A) 0.5 m/s
(B) 1 m/s
(C) 2.5 m/s
(D) 5 m/s
(E) 25 m/s</p></li>
<li><p>A 3 N force is exerted on an infinitely large wheel of moment of interial 12 kgm^2. At what distance from the center of the wheel should the force be exerted in order for the wheel to accelerate with an angular acceleration of 2 rad/s^2, assuming the force is exerted perpendicular to the radius of the wheel in the plane of the wheel?
(A) 6 m
(B) 8 m
(C) 12 m
(D) 16 m
(E) 18 m</p></li>
<li><p>A mass m oscillates on a spring of spring constant k with an amplitude A. What is the maximum velocity of the mass?
(A) A
(B) A(k/m)
(C) A(m/k)
(D) A<em>sqrt(k/m)
(E) A</em>sqrt(m/k)</p></li>
<li><p>A pendulum swinging with a maximum amplitude of pi/6 has a period of T. If the maximum amplitude is increased to pi/3, what is the new period of the pendulum?
(A) T/4
(B) T/2
(C) T
(D) 2T
(E) 4T</p></li>
<li><p>A pendulum swings in simple harmonic motion with period T and angular displacement theta. If the same pendulum is instead raised to an initial displacement of 3theta, the new period will be
(A) T/9
(B) T/3
(C) T
(D) 3T
(E) 9T</p></li>
</ol>
<p>Please help me with these. Thanks. I have a midterm this wednesday.</p>