<p>matty, you know they give you that value on the formula charts.</p>
<p>oops lol
stupid me.</p>
<p>the H in mgH was xsintheta + h, just lettin you know</p>
<p>crap, i just realized i multiplied by the slope instead of the inverse on number 3. how much credit do you think they'll give me. i even had x^2/v^2 written and wasn't really paying attention.</p>
<p>carried errors = full credit for all but that part of the problem...which is why I'm feeling confident that I got a combined 15 on the first two E and M FR....</p>
<p>what exactly were they looking for in 1b,c?</p>
<p>on mechanics, it was normal force and coefficient of friction for 1b and 1c</p>
<p>i know what it literally asked for, lol. what were they looking for in the answer?</p>
<p>oh oops. for normal force it was mg - Fsintheta.</p>
<p>thats what i put, but what about the "derive" part? was anything else needed besides what you said above?</p>
<p>for coefficient of friction i put (Fcostheta - ma)/(mg + Fsintheta)</p>
<p>i don't remember a "derive" part, so i don't think i put anything else for that</p>
<p>By "derive," they meant obtain a formula, not the calculus definition of the word.</p>
<p>I totally screwed up a lot of #2. </p>
<p>Does anybody know what the minimum raw score is to get a 5 normally?</p>
<p>low to mid 50s</p>
<p>what equation were we supposed use for part a of question 2???</p>
<p>distance = velocity/time</p>
<p>radius = distance/2pi because its a circular orbit</p>
<p>(Fcostheta - ma)/(mg + Fsintheta) should read:</p>
<p>(Fcostheta - ma)/(mg - Fsintheta)...it should be a negative sign in the denominator!!! Otherwise that is exactly what I got!!!</p>
<p>noo...kepler laws still apply if its a circular orbit...its only if its an elliptical orbit u use the semimajor radius</p>
<p>right, a circle is just a special case of an ellipse.</p>