<p>does anyone know how to calculate the composite score for apes exam
and generall what the curve is?</p>
<p>is there a set point total for the FRQ on enviro?</p>
<p>thanks</p>
<p>The MC is out of 100, take that final score with the .25 pt reductions for each wrong answer and multiply by .6, then take the FRQ score (4 questions of 10 pts each) and add it to the number you have
61+= 5</p>
<p>^^^^
Thanks!</p>
<p>There is a constant that each of the FRQs are multiplied by and the same for free response. Composite score needs to be 120 out of 150 for a 5. The constant is different every year though. I’m assuming for FRQs though, that it is 1.5.</p>
<p>120/150…isnt that a bit high?</p>
<p>No, I checked on an earlier exam. You really need about 75% to get a 5 on this test.</p>
<p>No, it’s closer to 60-65%</p>
<p>SO MANY NUMBERS!!!</p>
<p>But then again, if ~30% get a 1, I think it should be ~60%. If not… I’ll be screwed. lol</p>
<p>75% does seem unrealisctically high for a 5, especially on an AP Exam.</p>
<p>So does anyone know which it is? </p>
<p>[MC correct - MC wrong(.25)] * .66 + [number of points for each FR (out of 10)] *.33
60-65+ = 5</p>
<p>or the more complicated method that Shizzle gave?</p>
<p>Ive seen it done both ways (the first way in PR, the second way in Kaplan- I think)</p>
<p>No, the easiest way to make the first part worth 60% and the FRQ worth 40% is just
(MC correct - (MC wrong(.25)*.6 + Total FRQ points</p>
<p>60% is too low for environmental science. Chem requires 67% for a 5 and it is a very heavily curved test. So one would expect 70-75% for APES.</p>
<p>Around a 91+/150 is a 5 (which is approximately 61%).</p>
<p>(MC correct - 0.25xMC incorrect) + FRx1.5 = #/150</p>
<p>Ok, I check my PR book.
[(MC correct - 0.25<em>MC incorrect)</em>0.9]+[1.5<em>FRQ]= score
For example, someone gets 100/100 on MC and 40/40 on FR.
The score would be (100</em>9)+(1.5*40)=150, which is the total score.</p>
<p>For a five, you need to get around 91/150 or above.</p>