<p>How do you do this one?</p>
<p>bump 10char</p>
<p>perimeter: CT + arcSBT + SA + AC</p>
<ol>
<li>find arc length
(pi x r x degree )/ 180 = 3pi</li>
<li>the diagonal of the rectangle is = to the radius (draw the 2nd diagonal and ull see it) so thats 6</li>
<li>then if do RC is equal to 1,2,4,5,6 you will get that
RC CT RA SA
0 6 8 not possible
1 5 7 not possible
2 4 6 0 (not possible)
3 3 5 1
4 2 4 2
5 1 3 3
6 0 2 4</li>
</ol>
<p>You can get this data by knowing that the radius is 6 and the L + W = 8
so the only #s that work in this case are when RC is equal to 3,4,5,6
if RC is = to 4 then the rectangle is in fact a square which does not work
so now 3,5,6 are left
if you use RC as 5 and 6 (in perimeter: CT + arcSBT + SA + AC)
you get two answer choices that are NOT available. and IF you look at the diagram, it looks like the rectangle is bisecting line RCT.
thus,
1+6+3+3pi (B) is your answer…</p>
<p>This is a hard problem. Main thing is seeing that RB = 6 (it is the radius), so that AC = 6.</p>
<p>Then, perimeter = arc + TC + CA + SA.</p>
<p>But, TC = 6 - (width of rectangle) and SA = 6 - (length of rectangle).</p>
<p>So, perimeter = 3pi + (6 - width) + 6 + (6 - length) = 3pi + 18 - (length+width) = 3pi + 18 - 8 = 3pi + 10.</p>
<p>this is one of the toughest problems i’ve ever seen on the SAT haha…</p>
<p>but yeah,</p>
<p>arc length is 1/4 of circumference. ends up being 3pi.</p>
<p>diagonal in rectangle = radius = 6</p>
<p>length + width = 8</p>
<p>the rest of the circumference is found by radius + radius - length - width.</p>
<p>6 + 6 - (8) = 4</p>
<p>add em up. 6 + 4 + 3pi.</p>
<p>=D</p>
<p>thanks, didnt see that</p>