<p>It is not in the topic already, I searched. But if you could help with this question, I would appreciate it.</p>
<p>There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then, in terms of n, what percent of those enrolled are men?</p>
<p>Thanks</p>
<p>w (women)=n (men)+75
total students = w + n = n + 75 + n = 2n+75
%men = (#men/#total students) x 100 = 100n/(2n+75)</p>
<p>plug in numbers.....
let n=10 then there are 85 women and 10 men
so, men/total students=percent men, so 10/(85+10)=10/95=approx. .105
then go through the answer choices and plug in what you let n=10 and then see which gives you the approx. .105 which would need to be about 10.5 percent if they give it in percent</p>
<p>such that------ 100 x 10/2(10)+75= 1000/95=10.5% so your answer would be that one because your percent of men would be equal </p>
<p>**you need to remember that what you solve for (.105) is just the decimal and what you get out of the answer choices will be percent, the easy way to get away from this is to make sure that you convert the .105 off the bat to percent, thus 10.5 percent</p>