<p>I would copy the question here, but it involves a geometric shape.</p>
<p>Does anyone have any input? I really have no idea how to go about with it. Thanks in advance.</p>
<p>because all 5 segments are congruent, you can let them be any length you want them to be, so let’s say that all 5 segments equal length 1</p>
<p>If all 3 sides of an equallateral triangle are the same length, then all 3 angles must be equal as well. Since the sum of the interior angles of any triangle is 180 degrees, we know that <DAB is 60 degrees, <ADB is 60 degrees, and <ABD is 60 degrees</p>
<p>Line AC bisects angle ADB (cuts the angle in half), so the new line cuts a new angle <ADC, and this new angle is 30 degrees. This angle also cuts triangle ADB into 2 equllly sized
30-60-90 triangles. </p>
<p>Since line AD is length 1 and line DB is length 1/2, then we know the line extending from point A to line BD is equal to (sqrt (3)/2). AC is twice that lenght, therefore AC = sqrt (3)</p>
<p>If AC= sqrt (3) and BD = 1, then the ratio of AC to BD equals sqrt(3) to 1</p>
<p>Thank you very much!</p>
<p>Ahh! I was having problem with the same question! Thank you so much!</p>