<p>Hi,</p>
<pre><code> Can anybody explain how to evaluate the integral using a calculator? I know this is a dumb question.............
</code></pre>
<p>Hi,</p>
<pre><code> Can anybody explain how to evaluate the integral using a calculator? I know this is a dumb question.............
</code></pre>
<p>anyone? plz........i am taking the late test next Wed!!</p>
<p>thanks.</p>
<p>What calculator?</p>
<p>assuming u have the ti 83/84(+) family you can evaluate an integral numerically by going to
math->fnint
and type in the integral with the syntax
fnint(f(x),x,lower bound,upper bound).
Or basically the function, what it's in terms of, followed by the bounds.</p>
<p>On the 89 it's similar but u can evaluate an indefinite integral as well (and you MUST close your parentheses).</p>
<p>Here is an example. Pretend you wanted to find the integral of x^2 from 0 to 2. </p>
<p>You would type in</p>
<p>Fint (x^2, x, 0, 2). MAKE SURE you put the correct amount of paranthesis and everything like so. IF you don't you get errors or sometimes wrong answers.</p>
<p>And once you go to math -> fint make sure you don't accidentaily go to int). Its the wrong command and thats for a step function.</p>
<p>On the 89, use the F3 menu and then pick Integrate( ) . In the parentheses put the expression, x, lower bound, upper bound. If it is in definite, leave off the bounds. Make sure to close all parentheses. :)</p>
<p>thanks so much..you guys.............</p>
<p>I really appreciate......! :)</p>
<p>sorry.i have another question</p>
<p>wut if the question asks me to calculate the enclosed area , say by x^2, and X^3..then wut should I do.?</p>
<p>^^^ For that, you first should graph the two equations. To find the area between two curves, you take the integral from the set limits of the top graph (in this case it would be x^3) and subtract the lower equation (which would be x^2)</p>
<p>Hopefully I explained that well.</p>
<p>yeah.....thanks......</p>
<p>you are a very good teacher......llol</p>
<p>sorry, one more question.</p>
<p>how do you use calculator to solve an equation , eg. x^1/2, and e^-3x...do you just graph the 2 funtions and zoom in......but how do you know if your answer is close enough to be considered accurate.</p>
<p>Use the solve function on the calculator. I have a TI-89 Titanium and you press F2 and then solve. You just type in, for example:</p>
<p>solve(2x^2=5x^3+3x,x)</p>
<p>And hit enter and you've got your answer. When you're done doing that, don't forget to clear your variables by going to F6 and hitting clear all variables a-z. Hope that helped!</p>
<p>thank you so much skateboard 0924!:)</p>