<p>Okay its been 48 hours. Anyone already have their green book and feel like posting questions/answers. Thanks.</p>
<p>what's the situation with the blue book..can those be discussed?</p>
<p>what did u get for interval of conv.?</p>
<p>come on, answers, answers</p>
<p>I didn't get anything for interval of converg.
I messed up the AB one on the temper. of the rod
(I did a quadratic regression stupid me)
And I messed up the volume part on #1
And I screwed up like 2 parts of the Polar one
So yeah...
Anyone feel like scanning the free responses and posting them on a website????</p>
<p>I feel kinda weird putting the answers that I remember, and I don't have the book, so I'll wait till I get it. But please someone, post something, i'm dying to know</p>
<p>what did u put, for the values of polar, and reason, decreased/increased?</p>
<p>I think I got 35/18 less than or equal to x less than or equal to 37/18
for the interval of convergence. Probably not right though, the answers arent ususally that obscure.</p>
<p>I got between 1 and 5, and the endpoints</p>
<p>after 48 hours..this is a free response problem. SO i''m in the clear to discuss this i hope. i hope i did it right :/</p>
<p>i don't have my book...but i think this was #1.</p>
<p>f(x) = (1/4) + sin pi*x</p>
<p>g(x) = 4^-X</p>
<p>graph of two shaded regions...</p>
<p>region nearest y-axis had g(x) > f(x) , this region was called R?</p>
<p>second region had f(x) > g(x), this region was called S?</p>
<p>a) find area of region R.</p>
<p>since no range or intercepts were given...all we know is the lowerbound is 0. upper bound is found through intercept calculation by inputing both f(x) and g(x) into calculator. this comes out as .1782, could go to .17821805 if you want to be accurate.</p>
<p>area between curves is integral of upper curve - lower curve respect to X using lowerbound of 0 and upperbound of .1782.</p>
<p>INT [( (4^-x) - (1/4 + sin pi*X) ) ] 0 to .1782 </p>
<p>comes out to be [ -1/ln4 * (4^-X) - (x/4) + 1/pi cos pi*X ] from 0 to .1782. </p>
<p>i'm not genious...so i had to input this into the calculator. came out to be approximately .06475306 </p>
<p>b) Find Region of S?</p>
<p>same idea...cept now f(x) > g(x). range is now from first intercept point to 2nd intercept point. 2nd intercept would be found using intercept calculation on graphing calculator. 2nd intercept = 1. </p>
<p>area = INT [ F(x) - g(x)] from .1782 to 1</p>
<p>= INT [ ((1/4) + sin pi*x) - (4^-X) ] from .1782 to 1</p>
<p>= [ x/4 - 1/pi cos pi*x + 1/ln 4 (4^-X) ] from .1782 to 1</p>
<p>answer: aproximately . 4104 </p>
<p>c) Find volume of S revolved about y=-1. i think this was washer method. </p>
<p>int pi [ (R(X))^2 - (r(x))^2] </p>
<p>R(x) = f(x) +1</p>
<p>r(x) = g(x) +1</p>
<p>V = int pi [ (5/4 + sin pi*x) ^2 - (4^-X + 1) ^2 ] from .1782 to 1</p>
<p>i just pluged this in to calculator...</p>
<p>volume is approximately 4.559</p>
<p>hey, that's what I got. next question.</p>
<p>Okay question I got the areas and the volume answer but I didn't know how to set up the volume integral
I have a calc program that does it for you :-}
So I drew the graph and y=-1 and I wrote washer method and then the answer
Any possible partial credit on that?</p>
<p>can't even remember #2</p>
<p>i do remember number three was a simple AB problem. the velocity graph.</p>
<p>on the graph... x represented time in seconds. y represented velocity with respect to time. </p>
<p>a) find distance traveled. basically integral of velocity or area of region under velocity function. can't tell you exactly off the top of my head...but just split it into triangles/squares and calculate area. explain your reasoning blah blah.</p>
<p>b) find first derivative of V(t) at 4 and 20. 4 was undefined because the point was not differentiable (more than one tangent line or was it a CUSP?). to find it at 20 i used mean value theorem ... don't remember answer. basically slope of the line at that point.</p>
<p>c) create function for a(t). just set a(t) = positive slope from [a,b] , t= 0 from [b,c] t = negative slope from [c, d]</p>
<p>do not remember the numerical values of slope or the range of the three different values for the function of a(t)..but that was basic idea..</p>
<p>hope i got it right?</p>
<p>BCgoUSC: Yes man, you got points for finding the answer :) i think you only lose 1 point for not setting up the integral...but you get the other two points for mention washer method and the answer..</p>
<p>i'm pretty sure that's how they would calculate it</p>
<p>what'd you say about the question about the mean value theorem on that problem?</p>
<p>mean value theorm does not apply because its not continuous</p>
<p>,... or what the person below me said... but i know it didnt apply</p>
<p>I thought it wasn't differentiable at 20. The slopes didn't match up, did they?</p>
<p>Glad to hear that Dru
I can work a damn calculator thats for sure.
I made a 5 on AB last year and took BC this year and to this day, Volume still perplexes the hell out of me.</p>
<p>i thought that both v(4) and v(20) weren't differentiable... both points had diff limits for slope from left nd right. since the curve isnt diff. on all points the mean value theorem doesnt apply... right?</p>
<p>the first derivative of v(t) at any point is a(t).</p>
<p>first derivate of v(c) = v(b) - v(a) / b - a
c = 20</p>
<p>forgot what the numerical values for b and a were. i might be wrong...anyone else get this?</p>