Calculus help

<p>Does anyone have time to help me with a calculus assignment?</p>

<p>What kind of help? AB or BC?</p>

<p>AB. <a href=“http://vortex.bd.psu.edu/~sas56/Old-Courses/MA152/rollercoaster.pdf[/url]”>http://vortex.bd.psu.edu/~sas56/Old-Courses/MA152/rollercoaster.pdf&lt;/a&gt; Confused as crap on how to do this and will need some guidance.</p>

<p>What is the sum of the digits of your student ID number?</p>

<p>Also, state exactly what you need help in, and what you have done. I would hope no one here will simply DO your homework for you, but if you show us your train of thought, we may guide you in the correct direction. Show us every process you have completed so far, relevant equations, etc. as well as your attempts at questions you don’t know.</p>

<p>Derivative is</p>

<p>T/20 (cos(x/10)) + A + 2(x-8.75)T/(2*8.75^2) </p>

<ol>
<li>Whenever you want increase/decrease/rate of change, think derivative.</li>
<li>Find the absolute maximum and minimum. Again, derivatives, set to zero, find critical points, and evaluate to see which is highest. </li>
<li>This is referring to the 2nd derivative, or the rate of the rate of change. </li>
<li>I don’t understand what they’re asking by the “angle”. </li>
<li>Graph the 1st derivative</li>
<li>Graph the 2nd derivative</li>
<li>I don’t really follow what they mean by “angle.” </li>
<li>Find the height at H(0), H(10), H(20)…H(170), and square the heights + sum them to get the total support needed.
How would I find te increase and decrease with the derivative?</li>
</ol>

<p>I was going for process. If you show me your process, I can show you where you’re wrong or right. Or if you don’t know, show me what you think it should or could be, and somebody will point you in the right direction. Show your processes, not generic rules.</p>

<h1>4, I believe they want the angle with respect to the vertical. You need to find out where the curve would be the steepest, and then find out what the slope is in order to relate it to an angle. You could also probably solve it parametrically, but it’s easier the other way I said.</h1>

<h1>8 You need to utilize the function relationship given in words, and integrate that to find the area underneath the curve.</h1>

<p>I need it for 15 and 30. thanks!</p>

<p>do you messanger or something? the sum of the student ID’s are 15 and 30 ( i need both) i tried 1-3 please help!</p>

<p>My friend, you can solve them all as they are, and simply plug in 15 & 30 at the end. T is just a constant. </p>

<p>For your next post, show like this:

  1. The specific number/question of the problem
  2. Your attempt at the problem, all relevant equations and side notes, plug-ins, individual steps so I can follow. Write out how you attacked it, MATHEMATICALLY, not in words. Give your actual mathematic steps, not what you should do but what you did.</p>

<p>Engineer head i can scan my work to you and send itto you. whats your email? its easier if we are on IM i need help and i have dont/ attempted some but it would take forever to type it up.</p>

<h1>4, you need to find out where the curve is the STEEPEST (think!), and find the slope of the curve at that point. Then, utilizing the slope of the curve, you need to create a right triangle with that slope in order to figure out the angle with respect to the vertical.</h1>

<h1>8, very simple my friend. They have given you the equation you need in words. Figure out what the function is (not difficult), and integrate it with respect to x from the start, x=0?, to wherever the rollercoaster begins to go “underground.”</h1>

<p>Ok thanks but i still need 6 more suggestions on how to do it. if you can get on IM (facebook idc) then we can get this conversation done quickly. tommorrow is my last day in the class, and this is the last project. im in 10th grade taking calculus i understand what its asking i need to know how to do it</p>

<h1>4, think. After finding the slope, how could you figure out the angle? Draw a right triangle. Remember, m=(change in y)/(change in x). For the triangle, use the ratio of change in y : change in x for the two legs on the triangle. From there, how can you find the angle?</h1>

<h1>8, sorry I just reread the question.</h1>

<p>

looks about right, as long as you solved for the point where the path goes below the axis correctly - set the position equation equal to 0.</p>

<p>ok what about 1,2,3 5,6, and 7</p>

<h1>7, the angle part refers to the same method/values as for #4 (that’s probably why you had to find out #4). Just don’t forget to convert to radians. “+ number of tops” my guess would be 3, as there are 3 maximums, or “tops,” for the path.</h1>

<p>The rest, your description suggested you knew what to do. I hope you would, for you should be able to complete those steps fairly easy.</p>

<p>='( ok i still need help why cant you do them for me? i need my A please just do it since your so smart</p>