calculus pros needed

Test Preparation
1

<p>anyone know the crtical points for the equation e^(-x)sin^2x</p>

<p>thanks i dont remeber the rule for taking the derivative of e^( ).</p>

2

<p>Dx[e^u] = u'(e^u)</p>

3

<p>so id be (-e^-x)((sin^2)x) + (e^-x)(2sinx)(cosx)</p>

4

<p>that's right.. now just set that equal to 0 and solve</p>

5

<p>so the answer is 0?</p>