<p>2x+z=2y
2x+2y+z=20 -> (2x+z)+2y=20 -> 2y+2y=20 -> y=5;</p>
<p>thanks Tsenguun && Amu for the help i reallllllllly appreciate it!!</p>
<p>that's fine. i am even here practicing for math. kk. so we're much obliged to the one who put the probs here.</p>
<p>highhopes89: Was it 3x/m-nx=2 or 3x/(m-nx) = 2?</p>
<p>Tsenguun: I thought the rule is you can't solve it unless you have 3 equations?</p>
<p>Tsenguun is correct about the second problem you posted. I didn't see the trick. If only CC would allow EDITING for long amounts of time.</p>
<p>FOR BOTH POSSIBILITIES:</p>
<p>
<p>3x/(m-nx) = 2 3x = 2m - 2nx</p>
<p>See how that works? I just brought the bottom on the other side through multiplication. Now we should get all the TERMS with x on one side</p>
<p>3x = 2m - 2nx 3x + 2nx = 2m</p>
<p>We have a problem. All the terms with x are on the left side. However, we are finished with moving stuff around. But wait a minute...BOTH terms on the left have X in them. Can we factor X out? That would isolate it, wouldn't it?</p>
<p>3x + 2nx = 2m x(3 + 2n) = 2m</p>
<p>Now we can easily isolate X:</p>
<p>x(3 + 2n) = 2m x = 2m/(3 +2n)
</p>
<p>THIS IS PROBABLY WHAT YOU MEANT (I MUST HAVE MISINTERPRETED IT AT FIRST):</p>
<p>
<p>3x/m-nx = 2 3x/m = 2 + nx 3x = 2m + 2nx</p>
<p>See how that works? I just brought the bottom on the other side through multiplication. Now we should get all the TERMS with x on one side</p>
<p>3x = 2m + 2nx 3x - 2nx = 2m</p>
<p>We have a problem. All the terms with x are on the left side. However, we are finished with moving stuff around. But wait a minute...BOTH terms on the left have X in them. Can we factor X out? That would isolate it, wouldn't it?</p>
<p>3x - 2nx = 2m x(3 - 2n) = 2m</p>
<p>Now we can easily isolate X:</p>
<p>x(3 - 2n) = 2m x = 2m/(3 - 2n)
</p>
<p>yea, it can be solved when there are 2 equations along with 3 unknowns. I'm sure that you could have solved it, if you had seen it a bit more. That's kinda tricky, isn't it? Don't believe in all those rules. Just think about it by yourself. Again do not depend on the rules, or that will lead you this kinda situation again. </p>
<p>PS: Yea, I didn't know which one it was, because those two won't bring same results. kk</p>
<p>Amu it was
3x/(m-nx) = 2 and the answer u gave was correct :: x = 2m/(3 +2n)
srry for the confusion =D</p>
<p>and Tsenguun was right for the second equation .. the answer was 5</p>
<p>Hey highhopes89 did you name urself after the pink floyd song high hopes?</p>
<p>How the *uck do I do this Q?
Question:<br>
A small square region inside a larger square is shaded. The diagonal of the larger square is three times the diagonal of the small square in length. What fraction of the area of the larger square is not shaded ? </p>
<p>Options:<br>
8/9
1/9
1/3
2/3</p>
<p>C'mon math geniuses!!! Mayday</p>
<p>the answer is 8/9...</p>
<p>the large square's diagonal can be 3 and smaller square's can be 1. Finding the area for both yields 9/2 for the larger and 1/2 for the smaller. subtracting 9/2-1/2= the area of the large square that is not shaded 8/2. There fore, fraction of area not shaded/area of large square=8/9 of the large square</p>
<p>thnx a lot hoopsplaya. Beware of the cow that laughs!!!!</p>
<p>Tom has 7 times as many crayons as Dick and 3 times as many as Harry. If Dick has less than 21 crayons, what is the maximum number of crayons that Tom can have?
a. 105
b. 120
c. 140
d. 147
e. 63</p>
<p>I believe the answer is c) 140.</p>
<p>If Dick has less than 21 crayons, let's say the maximum he can have is 20.
Thus, Tom's maximum is 7 times 20 or 140.</p>
<p>^^How many crayons does Harry have?</p>
<p>Harry has 60 I think</p>
<p>if tom has 140 crayons and dick has 20 then harry must have 140/3 which is 46.66666666666666666666.....</p>
<p>haha.. okay maybe the answer is a
it's the only one that evenly divides by 7 and 3</p>
<p>Rebecca I dun understand how A is the answer. Could you explain it to me?</p>