<p>The transmitter A and B are on the same highway 100 miles apart. The radio signal from B can be received from radius of 60 miles in all directions from the B site. For how many miles along the highway can the radio signals of both stations be received?
Answer: 12</p>
<p>The sum of an infinite geometric series with first term a and common ratio r<1 is given by
a/(1-r). The sum of a given infinite geometric series is 200 and ratio is 0.15. What is the second term?
Answer: 25.5</p>
<p>The sum of an infinite geometric series with first term a and common ratio r<1 is given by
a/(1-r). The sum of a given infinite geometric series is 200 and ratio is 0.15. What is the second term?
Answer: 25.5</p>
<h2>Looks like question 60 of one of the act test booklets. So basically, you substitute all the numbers into the equation. </h2>
<p>Terms:
Sn: Sum o Infinite Terms
a: First Term </p>
<h2>r: common ratio</h2>
<p>Sn=(a)/(1-0.15)
200=(a)/(1-0.15)
(200)(1-0.15)=a
170=a
Careful: Don<code>t chose answer choice (J) which is conveniently 170. a is the FIRST term, the question is asking for the SECOND term. Just simply multiply 170 by the common ratio (0
.15)=25.5 and you</code>re golden after that. I hope this explanation makes sense, any questions just send me a pm, ill try my best to help you out!</p>
<p>The transmitter A and B are on the same highway 100 miles apart. The radio signal from B can be received from radius of 60 miles in all directions from the B site. For how many miles along the highway can the radio signals of both stations be received? </p>
<p>hmmmm question 54, eh?</p>
<p>picture the two transmitters are on the x axis. that puts transmitter B at 100 on the x-axis and A at the origin. As you can see in the picture, A’s signal goes to 52. Since B’s signal reaches 60 miles, it goes back to 40 on the x-axis (100-60=40). The overlapping territory is from 40 to 52 on the axis. 52-40=12</p>
<p>assuming this is #53…here’s what’s happening…you use the expression above to determine which angle you are referencing. cos[tan-1(a/b)] means that you are to find cos of the same angle that will be determined by inverse tan if tan=a/b. </p>
<p>tan=opposite leg/adjacent leg…for a to be the “opposite” and b to be “adjacent”, you must be referencing the angle on the right hand side of the diagram. </p>
<p>for that same angle, you now need to determine cos. cosine=adjacent leg/hypotenuse, so cos=b/sqrt(a2+b2)</p>