<p>I keep trying to use circumference to find the length of the arc, but all that is doing is adding pi into the equation, the answers for multiple choice are 8,9,12,15,or 16</p>
<p>Thank you very much.
The Question is from the Official Practice Exam 2009-2010 from CollegeBoard.</p>
<p>EDIT- i did it by seeing 12 was distance between each so the radius of each is 6, circumference is 2πr so i did that with 6, twice and divided by two because theyre only half circles…</p>
<p>You guys are right, the answer is 12pi. The MC answers have pi’s in them. But you have to be careful about assuming that the radius of each circle is 6 (post #2) because one of the semicircles in the figure is smaller than the other. Assuming that r is 6 works for this problem but it may not work in another problem like this. So we know the radius of both circles combined is 12. We plug that into the C=2rpi and get 24pi for the circumference of both. Since both are semicircles we divide that into 2 to get 12pi.</p>
<p>THERE WAS A MISTAKE WITH THIS QUESTION! CB messed up! I got a little card in my booklet saying this book has a mistake Section 9, question 5 the answer choices should be changed to
8pi
9pi
12pi
15pi
and 16pi from there you could obviously tell it is 5 pi</p>
<p>we already know there was a mistake, only the pi’s are missing. That doesn’t mean that you should get the question wrong or omit it. You should know the answer is 12.</p>
<p>I was just statingthe fact that cb admitted to this mistake it tends to trip someone up since less then 1% of the time there is a mistake it would actually hurt me if I always assumed that cb was making a mistake when my answer wasnt present so the answers 12pi</p>