CB is SUCH a liar on this math question

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1

<p>They stress that there are NO tedious calculations.
WTH
What about number 8 on the grid in section (the candidate one). HOW IS THIS NOT A TEDIOUS CALCULATION.?</p>

2

<p>tedious was the wxyz one. screw that. i looked at that on thought pshaw. or there was probably some super genious way to do it and i didn't see it.</p>

3

<p>wxyz was NOT tedious. it was purely logical.</p>

4

<p>WXYZ was just logic</p>

<p>aww.. tips hat to avant :)</p>

5

<p>i don't understand what was so hard about wxyz</p>

6

<p>well i did say there was some super genious way to do it.</p>

<p>how did yall do it anyways? i don't feel like perusing through the math thread.</p>

7

<p>X=W+Y+Z, W=Y+1, Z=W-5.</p>

<p>X is obviously the biggest. guess it to be 9. X = 3W-6. if x is 9, w is 5. z is 0. y is 4. done.</p>

8

<p>candidate took all of 10 seconds?</p>

9

<p>It was easy. I made W = 5 and Z = 0. Then figure out the rest. It took me 5 seconds.</p>

10

<p>yeah but figuring out what you had to do.. took the other 7 minutes and 55 seconds..</p>

11

<p>I think it was 9540 or some number that began with 9 and ended with 0. PURE LOGIC.</p>

12

<p>XYZW one should have taken all of three seconds.</p>

<p>Put x and z in terms of y.
x=3(y-1)
z=y-4</p>

<p>y<=4 with the first one and y>=4 with the second one... hence y=4.</p>

13

<p>And for the candidate question, no tedious calculation either. The difference was like 28k, the total # voters was 28 million--so the winning candidate got 1% more than the loser. The percents have to add to 100, so the winner must've gotten 50.5%.</p>

14

<p>i used algebra and got w = 3y - 3 and got stuck there,</p>

15

<p>
[quote]

They stress that there are NO tedious calculations.
WTH
What about number 8 on the grid in section (the candidate one). HOW IS THIS NOT A TEDIOUS CALCULATION.?

[/quote]
</p>

<p>Just because a question involves large powers of ten does not make it tedious. This is where a strong understanding of math comes into play.</p>

16

<p>how about the one with the 70 computer symbols that can make 6-digit and 4-digit codes, that asked how many times more the # of 6digit codes is than the #of 4 digit codes? please, oh please tell me that was experimental, because the answer choices were bizarre and none of them worked for me.</p>

17

<p>I started using all this fancy algebra for the WXYZ one... substitution of multiple systems and such, haha and I ended with like 3y = 3y... so then I was like 0!? And I randomly stuck in 0 for Z and ended with the answer :)

[QUOTE]
how about the one with the 70 computer symbols that can make 6-digit and 4-digit codes, that asked how many times more the # of 6digit codes is than the #of 4 digit codes? please, oh please tell me that was experimental, because the answer choices were bizarre and none of them worked for me.

[/QUOTE]

I think that's experimental, because I didn't have it...</p>

18

<p>Yeah, I overanalyzed this question too.
I was going to try the make x=9 method, but i ran out of time before I got to an answer =(</p>

<p>Does anyone remember if the question had 3 equations or 4? If there were only 3, it's pointless trying to solve using systems as you need 4 equations to solve for 4 variables anyways. -.-;;</p>

19

<p>just look over the math thread, it is explained several times.. you had to use the fact that the value of w must be 5-9 and then just plug in numbers till one works..</p>

20

<p>yeah and like someone said, you should've seen that 3 equations wouldn't allow for the solving of 4 variables</p>