Challenging math question (To me at least)

<p>If 0 <em>< x _< 8, and -1 _< y _< 3, which of the following gives the set of all possible values of xy? PS (</em>< means less than or equal to).</p>

<p>A) xy=4
B) 0 _< xy _< 24
C) -1 _< xy _< 11
D) -1 _< xy _< 24
E) -8 _< xy _< 24</p>

<p><a href=“http://talk.collegeconfidential.com/sat-preparation/967564-stupid-math-question.html[/url]”>http://talk.collegeconfidential.com/sat-preparation/967564-stupid-math-question.html&lt;/a&gt;&lt;/p&gt;

<p>(I’m not making fun of you – that was the title of the thread where this was discussed previously.)</p>

<p>Thanks a lot man!</p>

<p>Haha, just did this question yesterday,put the wrong answer but I caught myself. :-P</p>

<p>When you have a problem like this…do all the combinations of the numbers before and after X and Y, so there will be 4 in total…</p>

<p>0x-1=0
0x3=0
8x-1=-8
8x3=24</p>

<p>As you can see, you get -8 as the lowest and 24 as the highest, so any other combinations must be within these numbers…so I would go with E…</p>