<p>On a standardized test with a normal distribution, the mean was 64.3 and the standard deviation was 5.4. What is thhe best approximation of the percent of scores that fell between 61.6 and 75.1?</p>
<p>1) 38.2
2) 66.8
3) 68.2
4) 95</p>
<p>(x - average)/(standard deviation) vrs. (y - average)/(standard deviation)</p>
<p>or -0.5 vrs. 2 <--note, these are the z-scores
-0.5 = 30.85%
2 = 97.72%</p>
<p>97.72 - 30.85 = 66.87 or 66.8, I guess</p>
<p>66.8</p>
<p>reference: z-Score</a> Table</p>
<p>this is stats or sat2,not sat math =S</p>