Community College to Community College?

<p>I'm not sure if this is the right section to post this but I have a couple questions about the eligibility of staying in colleges. My brother has gone from doing poorly in one regular college then transferring to a community college. This year he has also been doing poorly (not managing at least a 2.0) in his community college and plans to just transfer to another community college. He has enrolled as full time then will either fail majority of classes or drop under full time status. I understand every university has different policies where while your attending if you don't remain eligible they can put you on academic probation, take away financial aid, and eventually dismiss you from the college. However, my question is, is it possible to continue to just transfer to different community colleges with open admission after doing poorly in a previous one? Will financial aid eventually be taken away for good? I am happy to see my brother get a fresh start but its sad to see him do so poorly and just keep transferring to "start over" again. Any feedback on the answer to those questions or where they are online would be greatly appreciated.</p>

<p>Financial aid:
In years past, eligible students could receive a Pell grant for nine years of schooling—a lifeline for needy students, including adults attending school part time or those who completed some college off and on over a span of years. Effective immediately and retroactively, students are only eligible for six full-time years of the grant. The decision affects any student who has been or will be in college, so if you’ve been receiving a Pell grant for eight years, for example, you are immediately excluded and ineligible for a grant next school year.
Something to think about if he isn’t close to being done. </p>

<p>Other things to consider. If/when we wants to transfer to a a four year university, they will ask him for college transcripts from ALL of the colleges he attended. They will see everything he he has been doing.</p>