<p>@hazierneglect: that would be correct if the interval was closed, but the interval is open so there is no way the answer can be zero. The range of the first part of the solution is -1<y<0, so the domain of the second part of the solution (abs(y)-y) is -1<y<0. The lowest value this can be is any number infinitely close to 0. The largest value this can be is any number infinitely close to 2. That is, the answer I believe can be 0<answer<2. Someone correct my math if it’s wrong plz :)</p>
<p>Can someone provide an explanation for #16 of the grid-in questions? I thought that question was INSANELY hard.</p>
<p>I’m fairly positive all the answers didn’t start with ru, because that wouldn’t make any sense. There needed to be 5 answers (A-E) and I personally can’t think of five sensible answers that start with ru=. But don’t stress it chances are you got that one correct, it was one of the first few I think so don’t worry.</p>
<p>@Ronaldofan94
27^x=ka, 3^6x = 81a^2 </p>
<p>You take the square root of 3^6x = 81a^2, and it changes to 3^3x = 9a. If you plug in 1 for x, it looks exactly the same as 27^x=ka, except its 9a instead of ka. So K=9</p>
<p>@worriedteenager I thought the given inequality was -1 < 2y < 0.</p>
<p>Oh yea you’re right, let me do that again then:</p>
<p>Domain and range (shouldn’t really be called that but w.e.) for first part of solution: -1<2y<0 = -1/2 < y < 0</p>
<p>Domain for second part of solution (domain of the function itself): -1/2 < y < 0
Range of abs(y)-y:
Lowest value is any value infinitely close to 0 and highest value is any value infinitely close to 1, therefore range is 0<answer<1</p>
<p>OK so for the one with the arcs it gives a radius of 8. You draw diagonal radii to make a square with area 64. This leaves you with two 3/4 circles of radius 8. Find the area of one and double it, giving you 96pi. Then add the 64 from the square.</p>
<p>It was my first time taking the SATs yesterday. FOr math I know I omitted about 9-11 total, and answered 5-6 wrong. What could my math score be???</p>
<p>@basstrumpet probably around a 520</p>
<p>That’s awful :(</p>
<p>I think I might go ahead and kill myself. I bubbled in 81 instead of 9. =(</p>
<p>mine for the circle question is probably the most complicated here lol. I made a square in each circle that started where each circle ended. So if the circles are completed and overlapped, then you see that the square leaves the circle with 4 equal sections, 1 of which is the overlapped part. So you find the area of the square which is (diagonal)^2/2 or 16^2 (diameter)/2 =128. Then to find the area of each of the four sections, you subtract the area osf the square from the area of the circle so we have 8^2pi-128 = 64pi-128 then divide by 4, so the area of each section is 16pi-32. Thus, the area of the figure is the area of the 2 circles minus the area of the overlapping sections and because there are TWO overlapping sections, the answer is 64pi + 64pi -2(16pi-32)= 128pi-32pi+64= 96pi+64.</p>
<p>Very good question in my opinion, one of the hardest i’ve ever seen. i spent about 10 minutes on that questoin</p>
<p>^“boss” solution.</p>
<p>Does anyone remember the question with the circle and two pieces were shaded and two were not? And it asked for x degrees?</p>
<p>@cortana431
10 minutes?! I spent like 2-3. I don’t see why everyone thought this October’s math was so difficult. It seemed relatively simple.</p>
<p>@emeric11
Whats the max number of Mondays that can be in the months of July and August together (there are 31 days in both months.)</p>
<p>@elementi no the math was very easy in my opinion. especially the grid ins, very straightforward. That was the only question that really made me think</p>
<p>@ Elementi, the answer was 9 if I’m remembering correctly.</p>
<p>@cortana431
Oh I see. So whats your reasoning on why some people think the curve will be easy?</p>
<p>@YellowDaisies
Oh, no. I was telling him what the question was.</p>
<p>@elementi. i’m not sure what you mean by easy. I personally think the curve will be average ~800 780 760 730 710 690</p>