<p>Does someone have the dimensions for cylinder so I can check to see if I got that answer? And for c(x) I got 45% 0.0 does Simone remember the numbers? Was that the pollution one? I remember getting 45% for something…maybe not the c(x) question, though.</p>
<p>Anyone remember the question with the 45 degree triangle area 12, the square, and the 8sqrt 3 hypotenuse? I think I said 12 for length FE.</p>
<p>How did we lose questions LOLOL</p>
<p>Multiple Choice:</p>
<p>a+b=70- triangle question, a,b,c
1024 for sequential question
f(2x)=(f(x))^2
1 for MINIMUM distance between points on circle
20 possible entrances/exits to monument
9 max number days
500 Closest integer to surface area of cylinder
None for if x is an even integer, which MUST be odd
1.3 sum of price of 1 soda and 1 pretzel
10 for average of X Y Z
96pi+64 - overlapping circles
36 - question with 86 as median in 101 consecutive numbers
3 - length of BD slope -2/3
90% - x% C(x) question 10x/101-x
5/12 Probability of something greater than 90 for pressure OR both or the other
s for the triangle question r=t and you had to solve for U
isosceles right triangle NOT possible (perimeter 12, integer side lengths)
256 cant remember
0 parallelogram, difference of parallel slopes
t^2-9 one with s^2-81 / s-9 =t^2
5 - 4.8 and 5.1 rounding
-2
y+2, something with y=x+2 or something
36 , lowest possible number in 101 consecutive integers, median 86
0 f(x)+g(x)=h(x) column question
.2 (ab+1)/5ab ab=>10^5 or 6
2 where f(x) and g(x) intersect
130 where two lines were perpendicular and two parallel, and you had to find y.
w = ru; r(t+u) = rt + w
87 for Joe…K + M = 3J –> together 348
(x/w)^2 > z; number line which one is true
x+y> z or something like that it was another number line question with wxyz and it was like w=-1.5 x=-.5 y=.5 z=1.5
12 Pentagon question and square side length
4 Largest value 2A-B from set
-3 for first negative number after 13, 9, 5
1/4 for 48 minutes to library
16 was the answer to something, but don’t remember the question
1/8 for the ratio of the arc lengths; two pairs of vertical angles (160 was given)</p>
<p>Grid-ins:</p>
<ol>
<li>4000 -boxes of candy price or pounds</li>
<li>402- random “solve for x”</li>
<li>22 - average # of members on wednesday</li>
<li>72 - Area of shaded area, rectangle and semicircle</li>
<li>2.5 y=(k-1)^2 point (3,10)</li>
<li>78 -angle of x in triangle with angle y,y,y</li>
<li>.8 = probability of MISmatching sweater +scarf</li>
<li>9 Solve for K 27^x=ka</li>
<li>.5 .25- -.25=.5 (1 answer to that absolute value of y question)</li>
<li>3600 - n=k^2 n divisible by 24 AND 10</li>
</ol>
<p>10/10 Gridins 38/44 Multiple Choice 48/54 Overall</p>
<p>We lost questions because a couple of those are wrong. The 1/8 ratio, for example, is 8. But a lot of the lists above have unnecessarily excluded some questions.</p>
<p>Was 4/25 an experimental answer? It asked for the ratio of the area of the small circle:large circle in a cone.</p>
<p>@desafinado yes I got that by doing trig, how did people use the given square in their calculations?</p>
<p>I don’t remember one with a pentagon, I had writing experimental.</p>
<p>^ It wasnt really a pentagon. It was i think a square with a triangle attached to it but it gave you extraneous numbers too</p>
<p>Can someone do the probability question about the scarves and sweaters? It was a grid in I think, and I guessed 4 (or 4/1).</p>
<p>Ok so you have 5 distinct scarves and 5 distinct sweaters. 1 scarf matches with exactly 1 sweater. WE want to find the probability of choosing a mismatched pair. </p>
<p>Without loss of generality, assume we first select a scarf. because it matches with exactly 1 sweater, the probability of choosing that sweater is 1/5. Thus, our answer, the probability of choosing any of the other sweaters, resulting in a mismatched pair, is 1-(1/5)= 4/5 or .8</p>
<p>Thank you! I just did 1* 4 but it was supposed to be like this If I wanted to do it the permutation way: 1 (or 5/5) * 4/5 = 4/5</p>
<p>no one remembers something about r(t+u) ru+w or something? the answer was rt=w.</p>
<p>@Seahawks: it was rt+w = r(t+u) = rt+ru, so w=ru, which is the answer.</p>
<p>all the answer choices had ru=__ right? if so, I got that right, I just misremembered.</p>
<p>Experimental Question?</p>
<p>There was one problem where it had triangle sharing a side with a square that was sharing a side with another triangle, and you had to find the length of one of the sides of the final triangle using data you were given about the first triangle, and one of the numbers was 24 or the square root of 24, and possibly 8*square root of 3. Did anyone NOT have that question? I’m really hoping it was experimental because I ran out of time.</p>
<p>Can someone explain grid-in number 17 (the one with abs(y)-y).
I put zero. Is this correct?</p>
<p>Sry it wasn’t experimental :(</p>
<p>@YellowDaisies: That was not experimental. The answer was 12.</p>
<p>0 wouldn’t work for the |y| - y. The set of answers would be 0 < |y| - y < 1 (not inclusive). I got that one wrong as well because I didn’t divide the initial inequality by 2, so I entered -.5 as y and got out 1.</p>
<p>worriedteenager do you remember if all the answer choices started with ru=__ ? I know I got w on the other side.</p>
<p>@ worriedteenager and notanenginner, Thanks! Such awful news though…</p>