<p>i recall a discussion about this before, but i'm too lazy to look for it.. and it was a while back, anyways...</p>
<p>logically, i'd assume that multiplying by three halves or vice versa would be how to convert the old scores to the new scale... IE 1400-->2100.. </p>
<p>however, I think people were saying this would not be so? </p>
<p>can someone explain this to me quickly, or give me a link to the old post?</p>
<p>ALSO... how many questions wrong, approximately, would a 2100 be? assuming i got 700 on all 3 sections... </p>
<p>thanks</p>
<p>multiply your verbal by two i guess?</p>
<p>Use ratios...</p>
<p>old score/1600 = new score/2400</p>
<p>I read a 2000 = about a 1360-1400</p>
<p>A 2100 = 1400 and 2000 = 1333.333333</p>
<p>Multiplying by 3/2 works I think..</p>
<p>what about fatigue...? longer test? more leniency? i hardly think the 1.5x comparison works</p>
<p>Well of course it can't factor that in, and those kinds of things are different for everyone, not to mention hard to measure. So I think I'll leave the conversion at that.</p>
<p>Take your old SAT, and add your SAT II Writing score to get the new score.</p>
<p>to the op: mathematically the 3/2 system or proportional system or etc works perfectly...
that is not what people mean when they say it does not equate--they believe that a score, converted proportionally, will be better than it used to be
for example, according to this belief a 2100 is better than an old 1400, and a 2200 is close to the "new 1500," according to speculation on these forums
this deflation is an attempt to account for the added section, fatigue, etc.</p>
<p>to compare scores and verify this you will have to wait for the official curve, and use that</p>
<p>use a ratio
old score/1600 = new score/2400
it would be inaccurate, however, because it doesn't factor the new section...you could either be really good or really bad at writing...it would be like saying everybody who gets a 1500 on their SAT has 750 verbal and 750 math. This is simply not true, therefore, you cannot convert it.</p>