<p>In a group of 10 people, 60 percent have brown eyes. Two people are to be selected at random from the group. What is the probability that neither person selected will have brown eyes?</p>
<p>probability = 6/45</p>
<p>4C2 / 10C2 = 6/45</p>
<p>Are you sure?</p>
<p>The first chance is 4/10, the second is 4/9, I get 16/90 or 8/45</p>
<p>could be that it's early for me :(</p>
<p>6 Brown-Eyed persons, 4 non-Brown-Eyed persons.
Chance that first person selected doesn't have brown eyes = 4/10 = 2/5</p>
<p>Now since you picked one person without brown eyes, you have 6 BEP and 3 non BEP.
Chance that second person doesn't have brown eyes = 3/9 = 1/3</p>
<p>Multiply them together, 1/3*2/5 = 2/15</p>
<p>yeah now I see it :P misread it lol</p>