<p>A pilot flies horizontally at 1200 km/h, at height h = 29 m above initially level ground. However, at time t = 0, the pilot begins to fly over ground sloping upward at angle θ = 8.4° (Figure 2-39). If the pilot does not change the airplane's heading, at what time t does the plane strike the ground? </p>
<p>i tried several times, i can't figure it out!
please help!</p>
<p>You’re right it’s easy:
I got .5893 seconds</p>
<p>how about you guys?</p>
<p>0.595552 seconds</p>
<p>a hint to OP: you have to use trigonometry to find the distance covered by the airplane until it hits the “rising” ground. ;)</p>
<p>0.5891 secs?</p>
<p>ok can someone explain? i got 195m for the horizontal distance until the hill rises 29 meters. then i did DA on the speed for m/s but the value i got would make it crash much sooner than .5… seconds. i got like .05… and since it’s 1200km/h it kinda makes sense to me.</p>
<p>(0.195/1200)x3600=0.585</p>
<p>my bad, an extra zero found it’s way in there. but how would you guys do it without a calc. there’s no way i can do trig. without one.</p>
<p>do you have a trig table? With a weird angle like 8.4 degrees you pretty much need a calculator</p>