"HARDEST" SAT 1 Math Questions

<p>true...by the way you use ti-89 titanium right? This calc is like god...cuz it saves me soo much time and gives me extra time work on checking hard problems like you mentioned</p>

<p>Nope. Ti-83.</p>

<p>how do you guys do so well in SAT math? 30 seconds or less?!</p>

<p><a href="http://www.drgarygruber.com/geniuschallenge.htm%5B/url%5D"&gt;http://www.drgarygruber.com/geniuschallenge.htm&lt;/a&gt;&lt;/p>

<p>anyone wanna answer and explain the last question, in detail?</p>

<p>Anyone can give me site, where a good manual is for making the SAT with TI-89</p>

<p>You don't need a manual. You just need to understand your calculator and have an understanding of the useful functions. It just takes useage. Solve is your friend - and never let yourself even do the most basic math work - EVERYONE makes simple mistakes.</p>

<p>is the answer 30 to that one problem?</p>

<p>Merudh, the answer is not 30. </p>

<p>Hint: I have posted a possible solution on CC in the past. It is not a very simple problem. </p>

<p>I could post a few hints or simply post the link. Just let me know.</p>

<p>Difficult, indeed. I've done all the easy stuff and I seem to be close, but I doubt that I am.</p>

<p>post the link I give up lol</p>

<p>yeahhh, please post the link.. I have no idea how to solve it and I am getting quite frustrated!</p>

<p>Okay. Here's the link. The thread is pretty long as I did not give the solution immediately but provided a series of hints to allow everyone the opportunity to finish it. I spent quite a bit of time solving it, so do not feel bad if it did not "jump" at you. </p>

<p><a href="http://www.collegeconfidential.com/cgi-bin/discus/show.cgi?69/80505%5B/url%5D"&gt;http://www.collegeconfidential.com/cgi-bin/discus/show.cgi?69/80505&lt;/a&gt;&lt;/p>

<p>If you want a "last" chance, you may want to check this image first:</p>

<p><a href="http://img48.*******/my.php?loc=img48&image=geometryproof.jpg&t=y%5B/url%5D"&gt;http://img48.*******/my.php?loc=img48&image=geometryproof.jpg&t=y&lt;/a&gt;&lt;/p>

<p>Have fun!</p>

<p>"9 radical(x) + 7 = 16, what is the value of x?"
Are you serious?
9sqrt(x) = 9
sqrt(x) = 1
x = 1</p>

<p>"(x+y)/(x-y) = 7 what is value of x/y"
x + y = 7(x - y)
x + y = 7x - 7y
8y = 6x
x/y = 8/6 = 4/3</p>

<p>5 = m^x, what is 5m?
5m = 5 * m = (m^x) * m = m^(x+1)</p>

<p>These aren't hard at all.</p>

<p>Possibly because the answers were already posted?</p>

<p>lol good one but pyro...people like us find this easy...but some don't keep that in mind that the purpose of posting those were for others to see and well your explanation will prolly help those who don't understand...learn how to do it and think in simple terms.</p>

<p>anyway you got any hard ones..post up =)</p>

<p>can u explain how (m^x) * m = m^(x+1) ?? i never learned that property</p>

<p>to get 5m, he multiplied both sides by m. (m^x) means m<em>m</em>m (do this x times). So if he multiplied it by m one more time, it becomes m^)(x+1) because he's multiplying it by m one more time.</p>

<p>tweek, to give a slightly more formal explanation:</p>

<p>One of the basic properties of exponents is that (a^b)<em>(a^c) = a^(b+c)
Remember that m is really the same thing as m^1. So (m^x)</em>(m^1) = m^(x+1)</p>

<p>HTH</p>

<p>sweet thanks pyroclastic... great explanation :D</p>

<h1>x>0 and y > 0, x ^3 is half of x ^ 2, and y ^3 is one-third of y^2, what is the value of x + y?</h1>

<p>x^3 = (1/2)x^2
x^3 - (1/2)x^2 = 0
x^2 (x - 1/2) = 0
x=0 or x=1/2
Given x>0 => x=1/2</p>

<p>Same way y=1/3
x+y = ...</p>