<p>What is the minimum number of moles of PbSO4 that must be used to prepare 1 liter of saturated PbSO4 solution at 25 C?(ksp at 25 C for PbSO4 = 1x10^8)
a) 1x10^-16 mol
b) 1x10^-8 mol
c) 1x10^-4 mol
d) 1x10^-2 mol
e) 1x10^-1 mol</p>
<p>Also, are the tests in the PR book easier than the real test?</p>
<p>I think you meant to say that the Ksp for PbSO4 is 1*10^-8, not to the positive 8.</p>
<p>Anyway, it's just a matter of setting up an equilibrium. You'll only need to use the products though (Pb(2+) and SO4(2-)) since the only reactant, lead (II) sulfate is solid (this is the way solubility problems work).</p>
<p>So you get Ksp=[Pb++][SO4(2-)]=1*10^-8. Since there is one mol of Pb and one mol SO4 produced per mole of PbSO4, you can write this as:</p>
<p>Ksp=(x)(x), in other words Ksp=x^2. So 1<em>10^-8=x^2. Solve for x and you get 1</em>10^-4. This is called the molar solubility of PbSO4 (in mol/L). So the answer is C.</p>
<p>The tests in PR are about as hard as the actual test.</p>
<p>Entropy only increases when there's a conversion from solid to liquid or liquid to gas or solid to gas, and when the # of gas moles total increases from the reactant side to the product side.</p>
<p>Hey, does anyone know how hard exactly the SAT chem test is? I'm planning on taking it in June, but I'm only in Honors Chem. Do I have a chance of breaking 700 if I self study, or is all the material on the test AP chem stuff??</p>
<p>I took the SAT II chem after only honors chem as well. I used PR to prepare and got a 760. However, AP chem would have made it much easier... I'm positive I would've gotten an 800 had I taken it after AP Chem.</p>