<p>Hi all.</p>
<p>I am trying to solve a math problem, but even though I am looking at the solution,which is provided by College board's site, I just can't figure out the solution, or even what the question is asking.
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<p>The solution from College board hasn't helped so far.</p>
<p>I circulated the parted that I didn't understand.
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<p>Thank you.</p>
<p>sqrt(x)=x^(1/2)
sqrt(ab)=sqrt(a)<em>sqrt(b)
a=2
b=m^2
sqrt(2)</em>sqrt((m^2))= sqrt(2)<em>m^(2^1/2)
=sqrt(2)</em>m^(2<em>1/2)=sqrt(2)</em>m^(1)
Therefore, sqrt(2m^2)=sqrt(2)<em>m=m</em>sqrt(2) which is what the solution says.</p>
<p>derp.</p>
<p>The base of the pyramid is a square, you might have seen that.
The square has each side of length ‘m’
So, the diagonal of a square (say d ) is given by
d^2 = m^2 + m^2 ( by using pythagoras theorem)</p>
<p>or, d^2 = 2(m^2)</p>
<p>or, d = m (2)^1/2</p>
<p>SO, length of PQ, which is half of ‘d’ is given by
the figure,</p>
<p>hope this helps, looks kinda messy though!</p>
<p>don’t think that’s right ^</p>
<p>Most of the troublesome questions have been solved a few times here. It really pays to search for a few words of the question and check the past threads.</p>
<p>Here is a quick result:</p>
<p><a href=“http://talk.collegeconfidential.com/sat-preparation/1192738-blue-book-2nd-ed-level-5-math-problem-help-please.html[/url]”>http://talk.collegeconfidential.com/sat-preparation/1192738-blue-book-2nd-ed-level-5-math-problem-help-please.html</a></p>
<p>Enjoy!</p>
<p>Thank you all.</p>
<p>The link in Xiggi reply is amazing. I got it in a few seconds.</p>
<p>Thank you so much. This forum is great!!!</p>
<p>I will use the search button next time.</p>
