<p>If n can be any integer such that 6 < sqrt(n) < 10, what is the difference between the largest possible value of n and the smallest possible value of n?
A) 2 B) 4 C) 16 D) 62 E) 64
The answer said D, but how?</p>
<p>D</p>
<p>Sqrt of 100 is 10 and since n must be an integer less than 100, the highest possible value of n is 99.</p>
<p>Sqrt of 36 is 6 and since n must be an integer greater than 36, the lowest possible value of n is 37.</p>
<p>99-37= 62, therefore, D.</p>