<p>A square on a coordinate grid has horizontal and vertical sides. The upper left vertex of the square is located at (-3,4). The perimeter of the square is 40 units.</p>
<p>What are the coordinates of the other three vertices?</p>
<p>How do you do this? I've never worked with measurements in coordinate form. If they had it in whole numbers ( if that makes sense) I would get this.</p>
<p>Length of side= 10 units (40/4=10)
Upper Right Vertex (7,4)
Lower Right Vertex (7,-6)
Lower Left Vertex (-3,-6)</p>
<p>Hw help problems not allowed, but whatever.</p>
<p>Squares have four equal sides – if the perimeter’s 40 then each side’s length is 10, if the sides are all horizontal and vertical then the upper right vertex is 10 to the right, the lower left ten below, and the lower right ten below and ten to the right of the point given. So (7, 4) (7, -6), and (-3, -6) are your vertices.</p>
<p>SO what is the area?</p>
<p>100?</p>
<p>yes…</p>
<p>you really shouldn’t be asking for hw help here, esp not if it’s a pretty easy problem</p>
<p>Four Quadrants, and a square is all equal sides.</p>
<p>So…</p>
<p>25% of the area is in each quadrant?</p>
<p>Last question I promise, lol. I feel so dumb.What is this? 7th grade work</p>
<p>then you don’t belong in the high school life thread…</p>
<p>
</p>
<p>Do you mean for the square in the original problem? 12% is in the upper left, 28% is in the upper right, 18% is in the lower left, 42% in the lower right.</p>
<p>
</p>
<p>Why are you even here then? Relax. You’re in middle school. Your grades don’t matter.</p>